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A research engineer is testing the effectiveness of the braking system of a car when it is driven in wet conditions - Edexcel - A-Level Maths Pure - Question 11 - 2019 - Paper 2

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Question 11

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A research engineer is testing the effectiveness of the braking system of a car when it is driven in wet conditions. The engineer measures and records the braking d... show full transcript

Worked Solution & Example Answer:A research engineer is testing the effectiveness of the braking system of a car when it is driven in wet conditions - Edexcel - A-Level Maths Pure - Question 11 - 2019 - Paper 2

Step 1

Explain how Figure 6 would lead the engineer to believe that the braking distance should be modelled by the formula

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Answer

Figure 6 shows a linear relationship between log_{10} d and log_{10} V, indicating that as the braking distance d increases, the speed V also increases exponentially. This suggests that d could be modeled as a power of V in the form d = kV^n, where n is a constant. The specific point (0, -1.77) indicates that when log_{10} V is -1.77, the corresponding value of log_{10} d is 0. This provides support for the model since the relationship appears to be consistent across the data points.

Step 2

Using the information given in Figure 5, with k = 0.017

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Answer

From Figure 5, we have a data point (30, 20), which represents V = 30 kmh^-1 and d = 20 m. Substituting this into the model, we get:

20 = 0.017 × 30^n

To isolate n, we first calculate:

20 / 0.017 = 30^n

Calculating the left-hand side yields:

1176.47 = 30^n

Now, take the logarithm base 10:

log_{10}(1176.47) = n × log_{10}(30)

Calculating gives:

n ≈ 2.08, rounded to 3 significant figures, gives n = 2.08.

Step 3

Use your formula to find out if Sean will be able to stop before reaching the puddle.

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Answer

First, calculate the stopping distance for Sean’s car driving at 60 kmh^-1 (or 60/3.6 m/s):

Stopping distance can be modeled with d = kV^n:

First convert speed: V = 60 kmh^-1 = 16.67 m/s.

Now substitute:

d = 0.017 × (16.67)^2.08

Calculating gives:

d ≈ 4.292 m.

Since the puddle is 100 m away, and Sean takes 0.8 seconds to react, during which he continues moving:

Distance covered during reaction time: 16.67 m/s × 0.8s = 13.336 m.

Thus, total distance until stop = stopping distance + distance during reaction = 13.336 m + 4.292 m = 17.628 m.

This is obviously less than 100 m, therefore Sean will be able to stop before reaching the puddle.

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