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Express $$ \frac{4x-1}{2(x-1)} - \frac{3}{2(x-1)(2x-1)} $$ as a single fraction in its simplest form - Edexcel - A-Level Maths Pure - Question 4 - 2011 - Paper 4

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Express--$$-\frac{4x-1}{2(x-1)}---\frac{3}{2(x-1)(2x-1)}-$$--as-a-single-fraction-in-its-simplest-form-Edexcel-A-Level Maths Pure-Question 4-2011-Paper 4.png

Express $$ \frac{4x-1}{2(x-1)} - \frac{3}{2(x-1)(2x-1)} $$ as a single fraction in its simplest form. Given that $$ f(x) = \frac{4x-1}{2(x-1)} - \frac{3}{2(x-1)(... show full transcript

Worked Solution & Example Answer:Express $$ \frac{4x-1}{2(x-1)} - \frac{3}{2(x-1)(2x-1)} $$ as a single fraction in its simplest form - Edexcel - A-Level Maths Pure - Question 4 - 2011 - Paper 4

Step 1

Hence differentiate f(x) and find f'(2)

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Answer

To differentiate f(x)=32x1f(x) = \frac{3}{2x-1}, we use the quotient rule:

Let:

  • u=3u = 3
  • v=2x1v = 2x - 1 Then:
  • u=0u' = 0
  • v=2v' = 2

According to the quotient rule:

f(x)=uvuvv2=0(2x1)3(2)(2x1)2=6(2x1)2f'(x) = \frac{u'v - uv'}{v^2} = \frac{0(2x-1) - 3(2)}{(2x-1)^2} = \frac{-6}{(2x-1)^2}

Now substituting x=2x=2:

f(2)=6(2(2)1)2=6(41)2=632=69=23f'(2) = \frac{-6}{(2(2)-1)^2} = \frac{-6}{(4-1)^2} = \frac{-6}{3^2} = \frac{-6}{9} = -\frac{2}{3}

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