Given that
f(x) = x^2 - 4x + 5
x ∈ ℝ
a) express f(x) in the form (x + a)^2 + b where a and b are integers to be found - Edexcel - A-Level Maths Pure - Question 4 - 2021 - Paper 1
Question 4
Given that
f(x) = x^2 - 4x + 5
x ∈ ℝ
a) express f(x) in the form (x + a)^2 + b where a and b are integers to be found.
The curve with equation y = f(x)
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Worked Solution & Example Answer:Given that
f(x) = x^2 - 4x + 5
x ∈ ℝ
a) express f(x) in the form (x + a)^2 + b where a and b are integers to be found - Edexcel - A-Level Maths Pure - Question 4 - 2021 - Paper 1
Step 1
a) express f(x) in the form (x + a)^2 + b where a and b are integers to be found.
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Answer
To express the function in the desired form, we will complete the square:
Start with the original function:
f(x)=x2−4x+5
Take the coefficient of x, which is -4, halve it to get -2, and square it to find 4.
Rewrite the function by adding and subtracting this square:
f(x)=(x2−4x+4)+5−4
This simplifies to:
f(x)=(x−2)2+1
Thus, we find that a = -2 and b = 1.
Step 2
b) Write down (i) the coordinates of P.
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Answer
The curve meets the y-axis where x = 0. Substituting x = 0 into f(x):
f(0)=(0−2)2+1=4+1=5
Therefore, the coordinates of P are (0, 5).
Step 3
b) Write down (ii) the coordinates of Q.
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Answer
To find the coordinates of Q, we need the x-coordinate of the minimum turning point. Since this is at the vertex of the parabola, for the expression (x - 2)^2 + 1, the vertex occurs at x = 2. Substituting x = 2 into f(x):