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Express $$\frac{2(3x+2)}{9x^2 - 4} - \frac{2}{3x+1}$$ as a single fraction in its simplest form. - Edexcel - A-Level Maths Pure - Question 3 - 2012 - Paper 5

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Express--$$\frac{2(3x+2)}{9x^2---4}---\frac{2}{3x+1}$$--as-a-single-fraction-in-its-simplest-form.-Edexcel-A-Level Maths Pure-Question 3-2012-Paper 5.png

Express $$\frac{2(3x+2)}{9x^2 - 4} - \frac{2}{3x+1}$$ as a single fraction in its simplest form.

Worked Solution & Example Answer:Express $$\frac{2(3x+2)}{9x^2 - 4} - \frac{2}{3x+1}$$ as a single fraction in its simplest form. - Edexcel - A-Level Maths Pure - Question 3 - 2012 - Paper 5

Step 1

Factorizing the denominator

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Answer

First, we need to factor the denominator of the first fraction. The expression 9x249x^2 - 4 can be factored using the difference of squares. Thus, we have:

9x24=(3x2)(3x+2)9x^2 - 4 = (3x - 2)(3x + 2)

Step 2

Eliminating the common factor

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Answer

Next, we can simplify the first fraction:

2(3x+2)(3x2)(3x+2)\frac{2(3x+2)}{(3x-2)(3x+2)}

Cancelling the common factor (3x+2)(3x + 2), it reduces to:

23x2\frac{2}{3x - 2}

Step 3

Finding a common denominator

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Answer

Now, we need a common denominator to combine the two fractions:

The second fraction is still ( \frac{2}{3x+1} ).

The common denominator for both fractions would be:

(3x2)(3x+1)(3x - 2)(3x + 1)

Step 4

Combining the fractions

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Answer

We can now rewrite both fractions with the common denominator:

23x223x+1=2(3x+1)2(3x2)(3x2)(3x+1)\frac{2}{3x - 2} - \frac{2}{3x + 1} = \frac{2(3x + 1) - 2(3x - 2)}{(3x - 2)(3x + 1)}

Simplifying the numerator:

2(3x+1)2(3x2)=6x+2(6x4)=2+4=62(3x + 1) - 2(3x - 2) = 6x + 2 - (6x - 4) = 2 + 4 = 6

Thus, we have:

6(3x2)(3x+1)\frac{6}{(3x - 2)(3x + 1)}

Step 5

Final simplification

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Answer

Hence, as a final answer, we express it as:

6(3x2)(3x+1)\frac{6}{(3x - 2)(3x + 1)}

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