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The mass, $m$ grams, of a radioactive substance, $t$ years after first being observed, is modelled by the equation $$m = 25e^{0.05t}$$ According to the model, a) find the mass of the radioactive substance six months after it was first observed, b) show that $ rac{dm}{dt} = km$, where $k$ is a constant to be found. - Edexcel - A-Level Maths Pure - Question 6 - 2017 - Paper 2

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The-mass,-$m$-grams,-of-a-radioactive-substance,-$t$-years-after-first-being-observed,-is-modelled-by-the-equation--$$m-=-25e^{0.05t}$$--According-to-the-model,--a)-find-the-mass-of-the-radioactive-substance-six-months-after-it-was-first-observed,--b)-show-that-$-rac{dm}{dt}-=-km$,-where-$k$-is-a-constant-to-be-found.-Edexcel-A-Level Maths Pure-Question 6-2017-Paper 2.png

The mass, $m$ grams, of a radioactive substance, $t$ years after first being observed, is modelled by the equation $$m = 25e^{0.05t}$$ According to the model, a) ... show full transcript

Worked Solution & Example Answer:The mass, $m$ grams, of a radioactive substance, $t$ years after first being observed, is modelled by the equation $$m = 25e^{0.05t}$$ According to the model, a) find the mass of the radioactive substance six months after it was first observed, b) show that $ rac{dm}{dt} = km$, where $k$ is a constant to be found. - Edexcel - A-Level Maths Pure - Question 6 - 2017 - Paper 2

Step 1

find the mass of the radioactive substance six months after it was first observed

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Answer

To find the mass of the radioactive substance six months after it was first observed, we need to substitute t=0.5t = 0.5 into the equation for mm.

Starting from the equation:

m=25e0.05tm = 25e^{0.05t}

Substituting in t=0.5t = 0.5:

m=25e0.05×0.5=25e0.025m = 25e^{0.05 \times 0.5} = 25e^{0.025}

Calculating e0.025e^{0.025}:

e0.0251.0253e^{0.025} \approx 1.0253

Now, substituting this value back into the equation:

m25×1.025324.4m \approx 25 \times 1.0253 \approx 24.4

Therefore, the mass of the radioactive substance six months after it was first observed is approximately 24.4 grams.

Step 2

show that \( \frac{dm}{dt} = km \), where k is a constant to be found

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Answer

To show that rac{dm}{dt} = km, we need to differentiate the equation for mm with respect to tt:

Starting with:

m=25e0.05tm = 25e^{0.05t}

Using the chain rule, we find:

dmdt=25ddt(e0.05t)=25(0.05e0.05t)\frac{dm}{dt} = 25 \cdot \frac{d}{dt}(e^{0.05t}) = 25 \cdot (0.05e^{0.05t})

This simplifies to:

dmdt=1.25e0.05t\frac{dm}{dt} = 1.25e^{0.05t}

Now, we can express mm in our equation:

Since m=25e0.05tm = 25e^{0.05t}, we can rewrite our derivative:

dmdt=0.05m\frac{dm}{dt} = 0.05m

Thus, we can identify that k=0.05k = 0.05, and therefore:

dmdt=km\frac{dm}{dt} = km

where k=0.05k = 0.05. This proves the statement.

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