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A circle has equation $$x^2 + y^2 - 10x + 16y = 80$$ (a) Find (i) the coordinates of the centre of the circle, (ii) the radius of the circle - Edexcel - A-Level Maths Pure - Question 3 - 2022 - Paper 1

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A-circle-has-equation--$$x^2-+-y^2---10x-+-16y-=-80$$--(a)-Find--(i)-the-coordinates-of-the-centre-of-the-circle,--(ii)-the-radius-of-the-circle-Edexcel-A-Level Maths Pure-Question 3-2022-Paper 1.png

A circle has equation $$x^2 + y^2 - 10x + 16y = 80$$ (a) Find (i) the coordinates of the centre of the circle, (ii) the radius of the circle. Given that P is th... show full transcript

Worked Solution & Example Answer:A circle has equation $$x^2 + y^2 - 10x + 16y = 80$$ (a) Find (i) the coordinates of the centre of the circle, (ii) the radius of the circle - Edexcel - A-Level Maths Pure - Question 3 - 2022 - Paper 1

Step 1

Find (i) the coordinates of the centre of the circle

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Answer

To determine the center of the circle given by the equation x2+y210x+16y=80x^2 + y^2 - 10x + 16y = 80, we first rewrite it in standard form by completing the square for both the x and y terms.

  1. Rearranging the equation: x210x+y2+16y=80x^2 - 10x + y^2 + 16y = 80

  2. Completing the square for the x terms: x210x=(x5)225x^2 - 10x = (x - 5)^2 - 25

  3. Completing the square for the y terms: y2+16y=(y+8)264y^2 + 16y = (y + 8)^2 - 64

  4. Substitute these into the equation: (x5)225+(y+8)264=80(x - 5)^2 - 25 + (y + 8)^2 - 64 = 80

  5. Simplifying gives: (x5)2+(y+8)2=169(x - 5)^2 + (y + 8)^2 = 169

Thus, the coordinates of the centre of the circle are at the point (5, -8).

Step 2

Find (ii) the radius of the circle

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Answer

From the standard form of the circle equation (x5)2+(y+8)2=169(x - 5)^2 + (y + 8)^2 = 169, the radius can be found directly as the square root of the constant on the right side. Therefore, the radius ( r ) is: r=169=13. r = \sqrt{169} = 13.

Hence, the radius of the circle is 13.

Step 3

Find (b) the exact length OP

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Answer

To find the point P on the circle that is furthest from the origin O(0, 0), we use the center of the circle (5, -8) and the radius, which is 13.

  1. The distance from the origin to the center of the circle is given by: d=(50)2+(80)2=25+64=89d = \sqrt{(5 - 0)^2 + (-8 - 0)^2} = \sqrt{25 + 64} = \sqrt{89}

  2. Since point P is the furthest point on the circle, we add the radius to this distance: OP=89+13OP = \sqrt{89} + 13

Thus, the exact length of OP is: OP=13+89 OP = 13 + \sqrt{89}

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