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Lewis played a game of space invaders - Edexcel - A-Level Maths Pure - Question 8 - 2013 - Paper 3

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Lewis played a game of space invaders. He scored points for each spaceship that he captured. Lewis scored 140 points for capturing his first spaceship. He scored 1... show full transcript

Worked Solution & Example Answer:Lewis played a game of space invaders - Edexcel - A-Level Maths Pure - Question 8 - 2013 - Paper 3

Step 1

Find the number of points that Lewis scored for capturing his 20th spaceship.

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Answer

The scoring for each spaceship follows an arithmetic sequence where the first term, a=140a = 140, and the common difference, d=20d = 20. The formula for the nthn^{th} term of an arithmetic sequence is given by: Tn=a+(n1)dT_n = a + (n - 1)d Substituting n=20n = 20: T20=140+(201)imes20=140+380=520T_{20} = 140 + (20 - 1) imes 20 = 140 + 380 = 520 Thus, Lewis scored 520 points for his 20th spaceship.

Step 2

Find the total number of points Lewis scored for capturing his first 20 spaceships.

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To find the total points scored for the first 20 spaceships, we use the sum formula for an arithmetic series: Sn=n2×(2a+(n1)d)S_n = \frac{n}{2} \times (2a + (n - 1)d) Where n=20n = 20, a=140a = 140, and d=20d = 20: S20=202×(2×140+(201)×20)S_{20} = \frac{20}{2} \times (2 \times 140 + (20 - 1) \times 20) Calculating: S20=10×(280+380)=10×660=6600S_{20} = 10 \times (280 + 380) = 10 \times 660 = 6600 Hence, the total number of points Lewis scored is 6600 points.

Step 3

Find the value of n.

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Given that Sian captured nn dragons and the total points scored was 8500, we can use the sum formula for an arithmetic sequence as before. For Sian, the first term a=300a = 300 and the nthn^{th} term is 700700: Using the formula: Sn=n2(a+l)S_n = \frac{n}{2} (a + l) Where ll is the last term: 8500=n2(300+700)8500 = \frac{n}{2} (300 + 700) This simplifies to: 8500=500n8500 = 500n Solving for nn gives: n=8500500=17n = \frac{8500}{500} = 17 Thus, the value of n is 17.

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