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A sequence of terms $a_1, a_2, a_3, \ldots$ is defined by: a_1 = 3 a_{n+1} = 8 - a_n (a) (i) Show that this sequence is periodic - Edexcel - A-Level Maths Pure - Question 5 - 2022 - Paper 2

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A-sequence-of-terms-$a_1,-a_2,-a_3,-\ldots$-is-defined-by:--a_1-=-3--a_{n+1}-=-8---a_n--(a)-(i)-Show-that-this-sequence-is-periodic-Edexcel-A-Level Maths Pure-Question 5-2022-Paper 2.png

A sequence of terms $a_1, a_2, a_3, \ldots$ is defined by: a_1 = 3 a_{n+1} = 8 - a_n (a) (i) Show that this sequence is periodic. (ii) State the order of this pe... show full transcript

Worked Solution & Example Answer:A sequence of terms $a_1, a_2, a_3, \ldots$ is defined by: a_1 = 3 a_{n+1} = 8 - a_n (a) (i) Show that this sequence is periodic - Edexcel - A-Level Maths Pure - Question 5 - 2022 - Paper 2

Step 1

Show that this sequence is periodic.

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Answer

To demonstrate that the sequence is periodic, we start by calculating the first few terms based on the recurrence relation:

  • a1=3a_1 = 3
  • a2=8a1=83=5a_2 = 8 - a_1 = 8 - 3 = 5
  • a3=8a2=85=3a_3 = 8 - a_2 = 8 - 5 = 3
  • a4=8a3=83=5a_4 = 8 - a_3 = 8 - 3 = 5

This gives us: a1=3a_1 = 3, a2=5a_2 = 5, a3=3a_3 = 3, a4=5a_4 = 5, and we can see a repeating pattern: 3,5,3,5,3, 5, 3, 5, \ldots.

Thus, the sequence is periodic with a period of 2.

Step 2

State the order of this periodic sequence.

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Answer

The order of this periodic sequence is 2, as it repeats every 2 terms.

Step 3

Find the value of \( \sum_{n=1}^{85} a_n \).

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Answer

The value of the sum can be calculated by recognizing that the sequence alternates between 3 and 5.

For 85 terms, we find the number of odd and even indexed terms:

  • Odd indexed: 43 terms are equal to 3 (since the first term is 3).
  • Even indexed: 42 terms are equal to 5.

Thus, we can calculate the sum as follows:

n=185an=433+425=129+210=339.\sum_{n=1}^{85} a_n = 43 \cdot 3 + 42 \cdot 5 = 129 + 210 = 339.

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