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Find $$\int \left( 3x^2 - \frac{4}{x} \right) dx$$ giving each term in its simplest form. - Edexcel - A-Level Maths Pure - Question 5 - 2013 - Paper 2

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Find-$$\int-\left(-3x^2---\frac{4}{x}-\right)-dx$$-giving-each-term-in-its-simplest-form.-Edexcel-A-Level Maths Pure-Question 5-2013-Paper 2.png

Find $$\int \left( 3x^2 - \frac{4}{x} \right) dx$$ giving each term in its simplest form.

Worked Solution & Example Answer:Find $$\int \left( 3x^2 - \frac{4}{x} \right) dx$$ giving each term in its simplest form. - Edexcel - A-Level Maths Pure - Question 5 - 2013 - Paper 2

Step 1

Find $$\int 3x^2 \, dx$$

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Answer

To integrate the term 3x23x^2, we apply the power rule of integration:

xndx=xn+1n+1+C,\int x^n \, dx = \frac{x^{n+1}}{n+1} + C, for n1n \neq -1.

Thus,

3x2dx=3x33=x3.\int 3x^2 \, dx = 3 \cdot \frac{x^{3}}{3} = x^{3}.

Step 2

Find $$\int -\frac{4}{x} \, dx$$

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Answer

For the term 4x-\frac{4}{x}, we recognize it as 4x1-4x^{-1}. The integral of this term is:

4x1dx=4lnx.\int -4x^{-1} \, dx = -4 \ln |x|.

Therefore,

4xdx=4lnx.\int -\frac{4}{x} \, dx = -4 \ln |x|.

Step 3

Combine the results

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Answer

Combining both results, we get:

(3x24x)dx=x34lnx+C,\int \left( 3x^2 - \frac{4}{x} \right) dx = x^3 - 4 \ln |x| + C,

where CC is the constant of integration.

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