A manufacturer produces a storage tank - Edexcel - A-Level Maths Pure - Question 1 - 2019 - Paper 2
Question 1
A manufacturer produces a storage tank.
The tank is modelled in the shape of a hollow circular cylinder closed at one end with a hemispherical shell at the other en... show full transcript
Worked Solution & Example Answer:A manufacturer produces a storage tank - Edexcel - A-Level Maths Pure - Question 1 - 2019 - Paper 2
Step 1
Show that, according to the model, the surface area of the tank, in m², is given by
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Answer
To find the surface area of the tank, we need to combine the surface areas of the cylindrical and hemispherical parts.
Surface Area of Cylinder: The lateral surface area of the cylinder is given by:
Ac=2imesextπimesrimesh
Surface Area of Hemisphere: The surface area of the hemisphere is:
Ah=2imesextπimesr2
Total Surface Area: Thus, the total surface area A of the tank is:
A=Ac+Ah=2imesextπimesrimesh+2imesextπimesr2
Volume Constraint: Since the volume V of the tank is given by:
V=extπr2h+32extπr3
and it equals 6 m³, we can rearrange to express h in terms of r:
h=πr26−32πr3
Substituting into Surface Area: Substitute h back into the total surface area equation to express it solely in terms of r:
A=2πr(πr26−32πr3)+2πr2
After simplifying, we arrive at:
A=r12+35πr2
Step 2
The manufacturer needs to minimise the surface area of the tank.
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Answer
To minimize the surface area, we differentiate the surface area function A with respect to r:
Differentiate A:
drdA=−r212+310πr
Set the derivative to zero:
0=−r212+310πr
Rearranging gives:
310πr=r212
Multiplying through by (r^2) leads us to:
310πr3−12=0
Step 3
Use calculus to find the radius of the tank for which the surface area is a minimum.
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Answer
Solve for r: From our previous equation:
310πr3=12
Therefore:
r3=10π36≈1.146...
This implies:
r≈1.046...ext(to3significantfigures)
Step 4
Calculate the minimum surface area of the tank, giving your answer to the nearest integer.
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Answer
Substituting r back into A: Using the value of r we found:
A≈1.04612+35π(1.046)2
Calculating this results in:
A≈17.20...
So, rounding to the nearest integer, the minimum surface area is:
A≈17