The circle C has radius 5 and touches the y-axis at the point (0, 9), as shown in Figure 4 - Edexcel - A-Level Maths Pure - Question 2 - 2012 - Paper 3
Question 2
The circle C has radius 5 and touches the y-axis at the point (0, 9), as shown in Figure 4.
(a) Write down an equation for the circle C, that is shown in Figure 4.
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Worked Solution & Example Answer:The circle C has radius 5 and touches the y-axis at the point (0, 9), as shown in Figure 4 - Edexcel - A-Level Maths Pure - Question 2 - 2012 - Paper 3
Step 1
Write down an equation for the circle C
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Answer
To find the equation of the circle C, we need the center and the radius. The center of the circle is at (5, 9) since it is 5 units away from the y-axis and touches it at (0, 9) with a radius of 5. The general form of the equation for a circle is:
(x−h)2+(y−k)2=r2
where ( (h, k) ) is the center and ( r ) is the radius. Thus, substituting the values,
(x−5)2+(y−9)2=52
which simplifies to:
(x−5)2+(y−9)2=25
Step 2
Find the length of PT
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Answer
To find the length of PT, we first need to determine the coordinates of point T where the tangent from P(8, -7) touches the circle C. Since PT is perpendicular to the radius CT, we find the coordinates of C which is (5, 9).
Calculate the distance PC:
PC=(8−5)2+(−7−9)2=32+(−16)2=9+256=265
Next, we use the relationship between the radius, PT, and PC:
PT2+CT2=PC2
where (CT = 5), hence:
PT2+52=265
PT2+25=265
PT2=265−25
PT2=240
Finally, calculate PT:
PT=240=16⋅15=415
Thus, the length of PT is (4\sqrt{15} \approx 15.49).