(i) Given that p and q are integers such that
$$pq$$ is even
use algebra to prove by contradiction that at least one of p or q is even - Edexcel - A-Level Maths Pure - Question 9 - 2022 - Paper 1
Question 9
(i) Given that p and q are integers such that
$$pq$$ is even
use algebra to prove by contradiction that at least one of p or q is even.
(ii) Given that x and y ar... show full transcript
Worked Solution & Example Answer:(i) Given that p and q are integers such that
$$pq$$ is even
use algebra to prove by contradiction that at least one of p or q is even - Edexcel - A-Level Maths Pure - Question 9 - 2022 - Paper 1
Step 1
Given that p and q are integers such that
$$pq$$ is even
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Answer
To prove that at least one of p or q is even using a proof by contradiction:
Assume both p and q are odd.
Let p be represented as p=2m+1 and q as q=2n+1, where m and n are integers.
Calculate pq: pq=(2m+1)(2n+1)=4mn+2m+2n+1
Rearranging gives us pq=2(2mn+m+n)+1
This indicates that pq is odd.
Arrive at a contradiction:
Since we began with the assumption that pq is even, we have reached a contradiction.
Therefore, at least one of p or q must be even.
Step 2
Given that x and y are integers such that
* $x < 0$
* $(x+y)^2 < 9x^2 + y^2$
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Answer
To show that y>4x:
Start with the given inequality:
We have (x+y)2<9x2+y2
Expanding (x+y)2 gives x2+2xy+y2<9x2+y2
Simplify the inequality:
By rearranging, we get 2xy<8x2
which simplifies to xy<4x2
Divide by x (note x < 0):
Since x<0, dividing both sides by x will reverse the inequality: y>4x
Thus, we have shown that under the given conditions, y>4x.