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Given that the binomial expansion of $(1 + kx)^4$, |kx| < 1, is 1 - 6x + Ax^2 + .. - Edexcel - A-Level Maths Pure - Question 4 - 2014 - Paper 7

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Given-that-the-binomial-expansion-of-$(1-+-kx)^4$,-|kx|-<-1,-is--1---6x-+-Ax^2-+-..-Edexcel-A-Level Maths Pure-Question 4-2014-Paper 7.png

Given that the binomial expansion of $(1 + kx)^4$, |kx| < 1, is 1 - 6x + Ax^2 + ... (a) find the value of the constant k, (b) find the value of the constant A, gi... show full transcript

Worked Solution & Example Answer:Given that the binomial expansion of $(1 + kx)^4$, |kx| < 1, is 1 - 6x + Ax^2 + .. - Edexcel - A-Level Maths Pure - Question 4 - 2014 - Paper 7

Step 1

find the value of the constant k

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Answer

To find the value of the constant kk, we start with the binomial expansion of (1+kx)4(1 + kx)^4:

(1+kx)4=1+4(kx)+6(kx)2+4(kx)3+(kx)4(1 + kx)^4 = 1 + 4(kx) + 6(kx)^2 + 4(kx)^3 + (kx)^4

From the given expansion, we know that the xx coefficient is -6. Therefore, we need to equate this to the term 4(kx)4(kx), which gives:

4k=64k = -6

Solving for kk:

k = rac{-6}{4} = - rac{3}{2}.

Step 2

find the value of the constant A, giving your answer in its simplest form

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Answer

Next, we will find the value of the constant AA. From the binomial expansion, the coefficient for x2x^2 is given by the term 6(kx)26(kx)^2:

Substituting k = - rac{3}{2}, we get:

A = 6 imes rac{-3}{2} imes rac{-3}{2} = 6 imes rac{9}{4} = rac{54}{4} = rac{27}{2}.

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