A competitor is running a 20 kilometre race - Edexcel - A-Level Maths Pure - Question 13 - 2019 - Paper 2
Question 13
A competitor is running a 20 kilometre race.
She runs each of the first 4 kilometres at a steady pace of 6 minutes per kilometre. After the first 4 kilometres, she ... show full transcript
Worked Solution & Example Answer:A competitor is running a 20 kilometre race - Edexcel - A-Level Maths Pure - Question 13 - 2019 - Paper 2
Step 1
show that her time to run the first 6 kilometres is estimated to be 36 minutes 55 seconds.
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Answer
To determine the time it takes to run the first 6 kilometres:
For the first 4 kilometres, the time taken is:
4 km × 6 min/km = 24 minutes.
For the 5th kilometre:
Previous time (6 min) × 1.05 = 6.3 minutes.
For the 6th kilometre:
Previous time (6.3 min) × 1.05 = 6.615 minutes.
Total time for the first 6 kilometres is:
extTotalTime=24+6.3+6.615=36.915extminutes
Converting 36.915 minutes into minutes and seconds:
36.915 minutes = 36 minutes and 55 seconds.
Step 2
show that her estimated time, in minutes, to run the rth kilometre, for 5 ≤ r < 20, is 6 × 1.05^{r - 4}.
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Answer
The time taken to run the rth kilometre can be expressed based on the previous kilometre's time:
For r = 5:
Time = 6 × 1.05^{5 - 4} = 6 × 1.05.
For r = 6:
Time = 6 × 1.05^{6 - 4} = 6 × 1.05^2.
For r = 7, it continues:
Time = 6 × 1.05^{7 - 4}.
Thus, the formula for the rth kilometre, where 5 ≤ r < 20, is:
extTime=6×1.05r−4.
Step 3
estimate the total time, in minutes and seconds, that she will take to complete the race.
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Answer
To estimate the total time for the whole 20 km race:
The time for the first 6 km is already calculated as 36.915 minutes.
For the remaining 14 km (from 7 to 20), we calculate:
extTotalTime=24+extSumfromr=5extto20(6×1.05r−4).
The series can be calculated using the formula for a geometric series:
Sum = a × (1 - r^n) / (1 - r), where a is the first term, r is the common ratio, and n is the number of terms.