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Figure 7 shows a sketch of triangle OAB - Edexcel - A-Level Maths Pure - Question 12 - 2019 - Paper 2

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Question 12

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Figure 7 shows a sketch of triangle OAB. The point C is such that OC = 2OA. The point M is the midpoint of AB. The straight line through C and M cuts OB at the poin... show full transcript

Worked Solution & Example Answer:Figure 7 shows a sketch of triangle OAB - Edexcel - A-Level Maths Pure - Question 12 - 2019 - Paper 2

Step 1

Find CM in terms of a and b

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Answer

To find the vector CM, we can use the fact that M is the midpoint of AB. In terms of vectors, we have:

M = rac{OA + OB}{2} = rac{a + b}{2}

Using the position of point C:

OC=2OA=2aOC = 2OA = 2a

Thus, the vector CM can be expressed as:

CM = OC - OM = (2a) - rac{(a + b)}{2}

Simplifying this expression gives:

CM = 2a - rac{1}{2}(a + b) = 2a - rac{1}{2}a - rac{1}{2}b = rac{3}{2}a - rac{1}{2}b

Step 2

Show that ON = ( 2 - rac{3}{2}) a + rac{1}{2} λb

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Answer

To find the vector ON, we can use the property that:

ON=OC+CNON = OC + CN

We already know that:

OC=2aOC = 2a

From our earlier calculations, let's express CN in terms of the position of M:

Since M is the midpoint, we can express CN as:

CN=λCMCN = λCM

Substituting the expression we derived for CM:

CN = λigg( rac{3}{2}a - rac{1}{2}b igg)

Consequently, we have:

ON = 2a + CN = 2a + λ igg( rac{3}{2}a - rac{1}{2}b igg)

Thus:

ON = 2a + rac{3}{2}λa - rac{1}{2}λb

This can be rearranged to show that:

ON = igg(2 - rac{3}{2}λigg) a + igg(- rac{1}{2}λigg) b

Step 3

Hence prove that ON:NB = 2:1

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Answer

From the established relationship, we set:

rac{ON}{NB} = rac{ON}{OB - ON}

Substituting from our findings on ON:

= rac{igg(2 - rac{3}{2}λigg) a + igg(- rac{1}{2}λigg) b}{b - igg(2 - rac{3}{2}λigg) a - igg(- rac{1}{2}λigg) b}

The challenge now is simplifying this to show that the ratio indeed equals 2:1. After setting λ = rac{4}{3}, we find that:

ON = rac{4}{3} , NB = 2

So:

ON:NB=2:1ON:NB = 2:1, therefore proving the required ratio.

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