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6. (a) Given that sin θ = 5 cos θ, find the value of tan θ - Edexcel - A-Level Maths Pure - Question 8 - 2006 - Paper 2

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6. (a) Given that sin θ = 5 cos θ, find the value of tan θ. (b) Hence, or otherwise, find the values of θ in the interval 0 ≤ θ < 360° for which sin θ = 5 cos θ, g... show full transcript

Worked Solution & Example Answer:6. (a) Given that sin θ = 5 cos θ, find the value of tan θ - Edexcel - A-Level Maths Pure - Question 8 - 2006 - Paper 2

Step 1

Given that sin θ = 5 cos θ, find the value of tan θ.

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Answer

To find the value of tan θ, we start with the given equation:

extsinθ=5extcosθ ext{sin } θ = 5 ext{ cos } θ

We can express tan θ in terms of sin and cos:

exttanθ=extsinθextcosθ=5extcosθextcosθ=5 ext{tan } θ = \frac{ ext{sin } θ}{ ext{cos } θ} = \frac{5 ext{ cos } θ}{ ext{cos } θ} = 5

Therefore, the value of tan θ is:

exttanθ=5 ext{tan } θ = 5

Step 2

Hence, or otherwise, find the values of θ in the interval 0 ≤ θ < 360° for which sin θ = 5 cos θ.

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Answer

We already established that tan θ = 5. Now we find the angle θ:

Using the inverse tangent function:

θ=an1(5)θ = an^{-1}(5)

Calculating this gives:

θ78.7°θ ≈ 78.7°

Since the tangent function is positive in both the first and third quadrants, we find the second solution by adding 180°:

θ=78.7°+180°258.7°θ = 78.7° + 180° ≈ 258.7°

Thus, the values of θ are approximately:

θ78.7°extand258.7°θ ≈ 78.7° ext{ and } 258.7°

Both answers are rounded to 1 decimal place.

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