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Given that $y = x^4 + 6x^{- rac{1}{2}}$, find in their simplest form (a) $\frac{dy}{dx}$ (b) $\int y \: dx$ - Edexcel - A-Level Maths Pure - Question 2 - 2012 - Paper 1

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Given-that---$y-=-x^4-+-6x^{--rac{1}{2}}$,-find-in-their-simplest-form---(a)-$\frac{dy}{dx}$---(b)-$\int-y-\:-dx$-Edexcel-A-Level Maths Pure-Question 2-2012-Paper 1.png

Given that $y = x^4 + 6x^{- rac{1}{2}}$, find in their simplest form (a) $\frac{dy}{dx}$ (b) $\int y \: dx$

Worked Solution & Example Answer:Given that $y = x^4 + 6x^{- rac{1}{2}}$, find in their simplest form (a) $\frac{dy}{dx}$ (b) $\int y \: dx$ - Edexcel - A-Level Maths Pure - Question 2 - 2012 - Paper 1

Step 1

(a) $\frac{dy}{dx}$

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Answer

To find rac{dy}{dx}, we will differentiate the function:

  1. Use the power rule for differentiation, which states that

    ddx(xn)=nxn1\frac{d}{dx}(x^n) = nx^{n-1}

  2. Differentiate each term in the expression:

    • For the first term x4x^4:

      ddx(x4)=4x3\frac{d}{dx}(x^4) = 4x^{3}

    • For the second term 6x^{- rac{1}{2}}:

      \frac{d}{dx}(6x^{- rac{1}{2}}) = 6 \cdot -\frac{1}{2} x^{- rac{3}{2}} = -3x^{- rac{3}{2}}

  3. Combine the results:

    \frac{dy}{dx} = 4x^{3} - 3x^{- rac{3}{2}}

    Therefore, the simplified form is:

    dydx=4x33x32\frac{dy}{dx} = 4x^{3} - \frac{3}{x^{\frac{3}{2}}}

Step 2

(b) $\int y \, dx$

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Answer

To calculate the integral ydx\, \int y \, dx where y = x^4 + 6x^{- rac{1}{2}}, we integrate each term separately:

  1. The integral of x4x^4 is:

    x4dx=x55\int x^4 \, dx = \frac{x^5}{5}

  2. The integral of 6x^{- rac{1}{2}} is:

    \int 6x^{- rac{1}{2}} \, dx = 6 \cdot \int x^{- rac{1}{2}} \, dx = 6 \cdot 2x^{\frac{1}{2}} = 12x^{\frac{1}{2}}

  3. Combine the results and add the constant of integration CC:

    ydx=x55+12x12+C\int y \, dx = \frac{x^5}{5} + 12x^{\frac{1}{2}} + C

Hence, the final answer is:

ydx=x55+12x12+C\int y \, dx = \frac{x^5}{5} + 12x^{\frac{1}{2}} + C

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