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Find, giving your answer to 3 significant figures where appropriate, the value of x for which (a) $3^x = 5$ - Edexcel - A-Level Maths Pure - Question 5 - 2005 - Paper 2

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Find, giving your answer to 3 significant figures where appropriate, the value of x for which (a) $3^x = 5$. (b) $ ext{log}_2(2x + 1) - ext{log}_2 x = 2$.

Worked Solution & Example Answer:Find, giving your answer to 3 significant figures where appropriate, the value of x for which (a) $3^x = 5$ - Edexcel - A-Level Maths Pure - Question 5 - 2005 - Paper 2

Step 1

(a) $3^x = 5$

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Answer

To solve the equation 3x=53^x = 5, we can take logarithms of both sides:

extlog3(3x)=extlog3(5) ext{log}_3(3^x) = ext{log}_3(5)

This simplifies to:

x=extlog3(5)x = ext{log}_3(5)

Using the change of base formula, we get:

x=extlog10(5)extlog10(3)x = \frac{ ext{log}_{10}(5)}{ ext{log}_{10}(3)}

Calculating this yields:

x1.464x \approx 1.464

Thus, to 3 significant figures, x=1.46x = 1.46.

Step 2

(b) $ ext{log}_2(2x + 1) - ext{log}_2 x = 2$

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Answer

We can use the properties of logarithms to combine the logs:

extlog2(2x+1x)=2 ext{log}_2 \left( \frac{2x + 1}{x} \right) = 2

By converting the logarithmic equation to its exponential form, we have:

2x+1x=22\frac{2x + 1}{x} = 2^2

which simplifies to:

2x+1x=4\frac{2x + 1}{x} = 4

Multiplying both sides by xx gives:

2x+1=4x2x + 1 = 4x

Rearranging yields:

1=4x2x1 = 4x - 2x

which results in:

1=2x1 = 2x

Thus,

x=12x = \frac{1}{2}

To check if there are other solutions:

x=0.5x = 0.5.

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