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Find \[\int \left(10x^4 - 4x - \frac{3}{\sqrt{x}} \right) dx\] giving each term in its simplest form. - Edexcel - A-Level Maths Pure - Question 4 - 2013 - Paper 1

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Find-\[\int-\left(10x^4---4x---\frac{3}{\sqrt{x}}-\right)-dx\]-giving-each-term-in-its-simplest-form.-Edexcel-A-Level Maths Pure-Question 4-2013-Paper 1.png

Find \[\int \left(10x^4 - 4x - \frac{3}{\sqrt{x}} \right) dx\] giving each term in its simplest form.

Worked Solution & Example Answer:Find \[\int \left(10x^4 - 4x - \frac{3}{\sqrt{x}} \right) dx\] giving each term in its simplest form. - Edexcel - A-Level Maths Pure - Question 4 - 2013 - Paper 1

Step 1

Step 1: Integrate Each Term

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Answer

To integrate each term separately:

  1. For the term 10x410x^4: [ \int 10x^4 , dx = 10 \cdot \frac{x^{5}}{5} = 2x^5 ]

  2. For the term 4x-4x: [ \int -4x , dx = -4 \cdot \frac{x^{2}}{2} = -2x^2 ]

  3. For the term 3x-\frac{3}{\sqrt{x}} (which can be rewritten as 3x12-3x^{-\frac{1}{2}}): [ \int -3x^{-\frac{1}{2}} , dx = -3 \cdot \frac{x^{\frac{1}{2}}}{\frac{1}{2}} = -6x^{\frac{1}{2}} ]

Step 2

Step 2: Combine the Results

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Answer

Combining all the integrated terms, we have: [2x^5 - 2x^2 - 6\sqrt{x} + C] where CC is the constant of integration.

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