Photo AI

2. Solve (a) $s^5 = 8$, giving your answer to 3 significant figures, (b) $ ext{log}_2 (x + 1) - ext{log}_2 x = ext{log}_2 7.$ - Edexcel - A-Level Maths Pure - Question 4 - 2005 - Paper 2

Question icon

Question 4

2.-Solve--(a)-$s^5-=-8$,-giving-your-answer-to-3-significant-figures,----(b)-$-ext{log}_2-(x-+-1)----ext{log}_2-x-=--ext{log}_2-7.$-Edexcel-A-Level Maths Pure-Question 4-2005-Paper 2.png

2. Solve (a) $s^5 = 8$, giving your answer to 3 significant figures, (b) $ ext{log}_2 (x + 1) - ext{log}_2 x = ext{log}_2 7.$

Worked Solution & Example Answer:2. Solve (a) $s^5 = 8$, giving your answer to 3 significant figures, (b) $ ext{log}_2 (x + 1) - ext{log}_2 x = ext{log}_2 7.$ - Edexcel - A-Level Maths Pure - Question 4 - 2005 - Paper 2

Step 1

Solve $s^5 = 8$, giving your answer to 3 significant figures

96%

114 rated

Answer

To solve the equation s5=8s^5 = 8, we first take the fifth root of both sides:

s=81/5s = 8^{1/5}

Calculating this, we find:

s=23/5=20.61.29s = 2^{3/5} = 2^{0.6} \approx 1.29

Thus, the answer is s1.29s \approx 1.29, which is expressed to three significant figures.

Step 2

log₂ (x + 1) - log₂ x = log₂ 7

99%

104 rated

Answer

Starting with the equation:

log2(x+1)log2x=log27,\text{log}_2 (x + 1) - \text{log}_2 x = \text{log}_2 7,

we can apply the properties of logarithms. This simplifies to:

log2(x+1x)=log27.\text{log}_2 \left(\frac{x + 1}{x}\right) = \text{log}_2 7.

Setting the arguments equal gives us:

x+1x=7,\frac{x + 1}{x} = 7,

which leads to:

x+1=7x.x + 1 = 7x.

Solving for xx, we get:

1=6xx=16.1 = 6x \Rightarrow x = \frac{1}{6}.

Thus, the solution is x=16x = \frac{1}{6}.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;