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Figure 1 shows a sketch of the curve with equation y = f(x) where f(x) = (x + 3)^{2} (x - 1), x ∈ ℝ - Edexcel - A-Level Maths Pure - Question 10 - 2013 - Paper 1

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Question 10

Figure-1-shows-a-sketch-of-the-curve-with-equation-y-=-f(x)-where-f(x)-=-(x-+-3)^{2}-(x---1),---x-∈-ℝ-Edexcel-A-Level Maths Pure-Question 10-2013-Paper 1.png

Figure 1 shows a sketch of the curve with equation y = f(x) where f(x) = (x + 3)^{2} (x - 1), x ∈ ℝ. The curve crosses the x-axis at (1, 0), touches it at (-3, 0)... show full transcript

Worked Solution & Example Answer:Figure 1 shows a sketch of the curve with equation y = f(x) where f(x) = (x + 3)^{2} (x - 1), x ∈ ℝ - Edexcel - A-Level Maths Pure - Question 10 - 2013 - Paper 1

Step 1

Sketch the curve C with equation y = f(x + 2)

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Answer

To sketch the curve C, we will apply a horizontal translation of the original function f(x). The transformation changes the input x to (x + 2), shifting the graph 2 units to the left. The x-intercepts will be adjusted as follows:

  1. The point (1, 0) shifts to (-1, 0).
  2. The point (-3, 0) shifts to (-5, 0).

Based on this, the x-intercepts for the new function are now at (-1, 0) and (-5, 0). The y-intercept can be found by substituting x = 0 into the equation for the curve C. We will find that the curve C meets the x-axis at the coordinates (-1, 0) and (-5, 0).

Step 2

Write down an equation of the curve C.

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Answer

The equation for the curve C can be expressed as:

(x+5)(x+1)(x1)(x + 5)(x + 1)(x - 1)

Here, we have factored the equation taking into account that the x-intercepts have changed due to the horizontal shift.

Step 3

Use your answer to part (b) to find the coordinates of the point where the curve C meets the y-axis.

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Answer

To find the coordinates of where the curve C meets the y-axis, we substitute x = 0 into the equation from part (b):

  1. Substitute x=0x = 0: (0+5)(0+1)(01)=511=5(0 + 5)(0 + 1)(0 - 1) = 5 \cdot 1 \cdot -1 = -5

Thus, the coordinates at the y-axis are (0, -5).

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