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6. (a) Write √80 in the form c√5, where c is a positive constant - Edexcel - A-Level Maths Pure - Question 8 - 2014 - Paper 1

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6. (a) Write √80 in the form c√5, where c is a positive constant. (b) A rectangle R has a length of (1 + √5) cm and an area of √80 cm². (b) Calculate the width of... show full transcript

Worked Solution & Example Answer:6. (a) Write √80 in the form c√5, where c is a positive constant - Edexcel - A-Level Maths Pure - Question 8 - 2014 - Paper 1

Step 1

Write √80 in the form c√5

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Answer

To express √80 in the desired form, we start by simplifying it:

80=(16imes5)=16imes5=45√80 = √(16 imes 5) = √16 imes √5 = 4√5

Hence, we can say that in the form c√5, c = 4.

Step 2

Calculate the width of R in cm.

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Answer

Given:

  • Length of the rectangle R = (1 + √5) cm
  • Area of rectangle R = √80 cm²

We can express the area of a rectangle as:

ext{Area} = ext{Length} imes ext{Width}\ ext{Width} = rac{ ext{Area}}{ ext{Length}}\

Substituting the known values:

ext{Width} = rac{√80}{1 + √5}\

To simplify this expression, we will rationalize the denominator. Multiplying both the numerator and the denominator by (1 - √5):

ext{Width} = rac{√80(1 - √5)}{(1 + √5)(1 - √5)} = \ rac{√80(1 - √5)}{1 - 5} = rac{√80(1 - √5)}{-4}\

This leads to:

ext{Width} = - rac{√80(1 - √5)}{4}\

Substituting √80 = 4√5:

ext{Width} = - rac{4√5(1 - √5)}{4} = -√5(1 - √5)\ = -√5 + 5\

Thus, the width can be expressed as: extWidth=55 ext{Width} = 5 - √5

This can be rewritten in the form p + q√5 as: 515=5+(1)55 - 1√5 = 5 + (-1)√5

This means p = 5 and q = -1.

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