Photo AI

Figure 1 shows the graph of equation $y = f(x)$ - Edexcel - A-Level Maths Pure - Question 3 - 2012 - Paper 6

Question icon

Question 3

Figure-1-shows-the-graph-of-equation-$y-=-f(x)$-Edexcel-A-Level Maths Pure-Question 3-2012-Paper 6.png

Figure 1 shows the graph of equation $y = f(x)$. The points $P(-3, 0)$ and $Q(2, -4)$ are stationary points on the graph. Sketch, on separate diagrams, the graph... show full transcript

Worked Solution & Example Answer:Figure 1 shows the graph of equation $y = f(x)$ - Edexcel - A-Level Maths Pure - Question 3 - 2012 - Paper 6

Step 1

Sketch $y = 3f(x + 2)$

96%

114 rated

Answer

To sketch the graph of y=3f(x+2)y = 3f(x + 2), follow these steps:

  1. Understanding the Transformation: The expression f(x+2)f(x + 2) indicates a horizontal shift of the graph of f(x)f(x) to the left by 2 units. The factor of 3 in front of ff indicates a vertical stretch by a factor of 3.

  2. Identifying Stationary Points: The stationary points of the original function are located at P(3,0)P(-3, 0) and Q(2,4)Q(2, -4). After shifting left by 2 units:

    • Point PP moves to (5,0)(-5, 0).
    • Point QQ moves to (0,4)(0, -4).
  3. Applying the Vertical Stretch: Applying a vertical stretch of 3 will modify the y-coordinates of the stationary points:

    • New point for PP: (5,3imes0)=(5,0)(-5, 3 imes 0) = (-5, 0).
    • New point for QQ: (0,3imes4)=(0,12)(0, 3 imes -4) = (0, -12).
  4. Drawing the Graph: Draw the transformed graph maintaining the shape of the original function while ensuring that the points (5,0)(-5, 0) and (0,12)(0, -12) are plotted correctly. Ensure the right section of the graph retains its characteristics as the original curve.

Step 2

Sketch $y = |f(x)|$

99%

104 rated

Answer

To sketch the graph of y=f(x)y = |f(x)|, consider the following:

  1. Understanding Absolute Values: The absolute value function, f(x)|f(x)|, transforms any negative y-values of f(x)f(x) to their positive counterparts, while keeping positive values unchanged.

  2. Identifying and Transforming Points: For the original points:

    • Stationary point P(3,0)P(-3, 0) remains unchanged since 00 is already non-negative.
    • The stationary point Q(2,4)Q(2, -4) will change to (2,4)(2, 4) because we take the absolute value of 4-4.
  3. Plotting the Graph: The new graph will reflect any part of the original function that is below the x-axis across to above the x-axis. Draw the usual shape for the above points, noting that the portion of the graph between (3,0)(-3, 0) and (2,4)(2, -4) will be reflected to (2,4)(2, 4).

  4. Final Touches: Ensure that all curves and points are combined to reflect the effect of taking absolute values, clearly displaying the new coordinates of the stationary points at P(3,0)P(-3, 0) and Q(2,4)Q(2, 4).

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;