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f(x) = x^4 - 4x - 8 - Edexcel - A-Level Maths Pure - Question 8 - 2007 - Paper 6

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Question 8

f(x)-=-x^4---4x---8-Edexcel-A-Level Maths Pure-Question 8-2007-Paper 6.png

f(x) = x^4 - 4x - 8. (a) Show that there is a root of f(x) = 0 in the interval [-2, -1]. (b) Find the coordinates of the turning point on the graph of y = f(x). (... show full transcript

Worked Solution & Example Answer:f(x) = x^4 - 4x - 8 - Edexcel - A-Level Maths Pure - Question 8 - 2007 - Paper 6

Step 1

Show that there is a root of f(x) = 0 in the interval [-2, -1]

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Answer

To find a root of the equation in the interval [-2, -1], we evaluate f at the endpoints:

  1. Calculate f(-2):

    f(2)=(2)44(2)8=16+88=16>0f(-2) = (-2)^4 - 4(-2) - 8 = 16 + 8 - 8 = 16 > 0

  2. Calculate f(-1):

    f(1)=(1)44(1)8=1+48=3<0f(-1) = (-1)^4 - 4(-1) - 8 = 1 + 4 - 8 = -3 < 0

Since f(-2) > 0 and f(-1) < 0, by the Intermediate Value Theorem, there must be a root in the interval [-2, -1] because of the sign change.

Step 2

Find the coordinates of the turning point on the graph of y = f(x)

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Answer

To find the turning point, we first find the derivative of f(x):

f(x)=4x34f'(x) = 4x^3 - 4

Setting this to zero to find critical points:

ightarrow x^3 = 1 ightarrow x = 1$$ Next, we calculate the corresponding y-coordinate: $$f(1) = (1)^4 - 4(1) - 8 = 1 - 4 - 8 = -11$$ Thus, the coordinates of the turning point are (1, -11).

Step 3

Given that f(x) = (x - 2)(x^2 + ax^2 + bx + c), find the values of the constants, a, b and c

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Answer

Expanding the expression:

f(x)=(x2)(x2+ax2+bx+c)=x3(1+a)+x2(b2)+c(2)f(x) = (x - 2)(x^2 + ax^2 + bx + c) = x^3(1 + a) + x^2(b - 2) + c(-2)

Comparing coefficients with the original polynomial, we need:

  1. The coefficient of x^3: 1+a=0ightarrowa=11 + a = 0 ightarrow a = -1
  2. The coefficient of x: b2=4ightarrowb=2b - 2 = -4 ightarrow b = -2
  3. The constant term: 2c=8ightarrowc=4-2c = -8 ightarrow c = 4

Thus, the values are: a=1,b=2,c=4.a = -1, b = -2, c = 4.

Step 4

In the space provided on page 21, sketch the graph of y = f(x)

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Answer

To sketch the graph:

  1. Mark the turning point (1, -11).
  2. Indicate the roots found from part (a) in the interval [-2, -1].
  3. Note the shape of the graph as it will approach infinity as x approaches ±∞, and it has a local maximum and minimum point.
  4. Draw the graph with a smooth curve, ensuring the end behavior is consistent with the leading coefficient being positive.

Step 5

Hence sketch the graph of y = |f(x)|

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Answer

For y = |f(x)|:

  1. Reflect the portion of the graph of f(x) that is below the x-axis (i.e., where f(x) < 0) to above the x-axis.
  2. Keep the portion that is above the x-axis unchanged.
  3. Ensure the graph remains smooth without sharp points.

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