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Express \[ \frac{3x + 5}{x^2 + x - 12} - \frac{2}{x - 3} \] as a single fraction in its simplest form. - Edexcel - A-Level Maths Pure - Question 3 - 2013 - Paper 8

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Express--\[-\frac{3x-+-5}{x^2-+-x---12}---\frac{2}{x---3}-\]--as-a-single-fraction-in-its-simplest-form.-Edexcel-A-Level Maths Pure-Question 3-2013-Paper 8.png

Express \[ \frac{3x + 5}{x^2 + x - 12} - \frac{2}{x - 3} \] as a single fraction in its simplest form.

Worked Solution & Example Answer:Express \[ \frac{3x + 5}{x^2 + x - 12} - \frac{2}{x - 3} \] as a single fraction in its simplest form. - Edexcel - A-Level Maths Pure - Question 3 - 2013 - Paper 8

Step 1

Factor the denominator

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Answer

We start by factoring the quadratic in the denominator:

[ x^2 + x - 12 = (x + 4)(x - 3) ]

Thus, we have:

[ \frac{3x + 5}{(x + 4)(x - 3)} - \frac{2}{x - 3} ]

Step 2

Combine the fractions

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Answer

To combine the fractions, we need a common denominator. The common denominator is ((x + 4)(x - 3)). Therefore:

[ \frac{3x + 5}{(x + 4)(x - 3)} - \frac{2(x + 4)}{(x - 3)(x + 4)} = \frac{3x + 5 - 2(x + 4)}{(x + 4)(x - 3)} ]

Step 3

Simplify the numerator

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Answer

Simplifying the numerator:

[ 3x + 5 - 2(x + 4) = 3x + 5 - 2x - 8 = x - 3 ]

So we have:

[ \frac{x - 3}{(x + 4)(x - 3)} ]

Step 4

Final Simplification

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Answer

The (x - 3) terms in the numerator and denominator cancel out:

[ \frac{1}{x + 4} ]

Thus, the final answer is:

[ \frac{1}{x + 4} ]

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