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The points A and B have coordinates (5, -1) and (13, 11) respectively - Edexcel - A-Level Maths Pure - Question 4 - 2005 - Paper 2

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The points A and B have coordinates (5, -1) and (13, 11) respectively. (a) Find the coordinates of the mid-point of AB. Given that AB is a diameter of the circle C... show full transcript

Worked Solution & Example Answer:The points A and B have coordinates (5, -1) and (13, 11) respectively - Edexcel - A-Level Maths Pure - Question 4 - 2005 - Paper 2

Step 1

(a) Find the coordinates of the mid-point of AB.

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Answer

To find the mid-point of line segment AB with coordinates A(5, -1) and B(13, 11), use the formula:

M=(x1+x22,y1+y22)M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)

Substituting the coordinates:

M=(5+132,1+112)=(182,102)=(9,5)M = \left( \frac{5 + 13}{2}, \frac{-1 + 11}{2} \right) = \left( \frac{18}{2}, \frac{10}{2} \right) = (9, 5)

Thus, the coordinates of the mid-point are (9, 5).

Step 2

(b) find an equation for C.

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Answer

Since AB is the diameter of circle C, the center of the circle is the mid-point of AB which we found to be (9, 5). The radius is the distance from the center to either endpoint A or B.

Calculating the radius (r):

Using point A(5, -1):

r=(95)2+(5(1))2=(4)2+(6)2=16+36=52r = \sqrt{(9 - 5)^2 + (5 - (-1))^2} = \sqrt{(4)^2 + (6)^2} = \sqrt{16 + 36} = \sqrt{52}

Now, the equation of the circle can be written as:

(x9)2+(y5)2=r2(x - 9)^2 + (y - 5)^2 = r^2

Substituting for r:

(x9)2+(y5)2=52(x - 9)^2 + (y - 5)^2 = 52

So, the equation for circle C is:

(x9)2+(y5)2=52(x - 9)^2 + (y - 5)^2 = 52

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