Photo AI

By taking logarithms of both sides, solve the equation $$4^{3p - 1} = 5^{210}$$ giving the value of $p$ to one decimal place. - Edexcel - A-Level Maths Pure - Question 3 - 2020 - Paper 1

Question icon

Question 3

By-taking-logarithms-of-both-sides,-solve-the-equation--$$4^{3p---1}-=-5^{210}$$--giving-the-value-of-$p$-to-one-decimal-place.-Edexcel-A-Level Maths Pure-Question 3-2020-Paper 1.png

By taking logarithms of both sides, solve the equation $$4^{3p - 1} = 5^{210}$$ giving the value of $p$ to one decimal place.

Worked Solution & Example Answer:By taking logarithms of both sides, solve the equation $$4^{3p - 1} = 5^{210}$$ giving the value of $p$ to one decimal place. - Edexcel - A-Level Maths Pure - Question 3 - 2020 - Paper 1

Step 1

Taking logarithms of both sides

96%

114 rated

Answer

First, apply logarithms to both sides of the equation:

extlog(43p1)=extlog(5210) ext{log}(4^{3p - 1}) = ext{log}(5^{210})

Using the power rule of logarithms, we can rewrite this as:

(3p1)log(4)=210log(5)(3p - 1) \cdot \text{log}(4) = 210 \cdot \text{log}(5)

Step 2

Isolating the term with $p$

99%

104 rated

Answer

Now, isolate the term containing pp:

3p1=210log(5)log(4)3p - 1 = \frac{210 \cdot \text{log}(5)}{\text{log}(4)}

Add 1 to both sides:

3p=210log(5)log(4)+13p = \frac{210 \cdot \text{log}(5)}{\text{log}(4)} + 1

Step 3

Solving for $p$

96%

101 rated

Answer

Finally, divide by 3 to solve for pp:

p=13(210log(5)log(4)+1)p = \frac{1}{3} \left( \frac{210 \cdot \text{log}(5)}{\text{log}(4)} + 1 \right)

Now, using a calculator,

  1. Calculate log(5)\text{log}(5) and log(4)\text{log}(4)
  2. Substitute these values into the expression for pp:

Calculating gives approximately p81.6p \approx 81.6.

Thus, the value of pp to one decimal place is 81.681.6.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;