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Magali is studying the mean total cloud cover, in oktas, for Leuchars in 1987 using data from the large data set - Edexcel - A-Level Maths Statistics - Question 4 - 2019 - Paper 1

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Magali is studying the mean total cloud cover, in oktas, for Leuchars in 1987 using data from the large data set. The daily mean total cloud cover for all 184 days f... show full transcript

Worked Solution & Example Answer:Magali is studying the mean total cloud cover, in oktas, for Leuchars in 1987 using data from the large data set - Edexcel - A-Level Maths Statistics - Question 4 - 2019 - Paper 1

Step 1

Find the probability that it has a daily mean total cloud cover of 6 or greater.

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Answer

To find the probability of selecting a day with a total cloud cover of 6 or more, we sum the frequencies for 6, 7, and 8:

P(X6)=P(X=6)+P(X=7)+P(X=8)=52+28+0184=80184=0.43478...0.4348P(X \geq 6) = P(X=6) + P(X=7) + P(X=8) = \frac{52 + 28 + 0}{184} = \frac{80}{184} = 0.43478... \approx 0.4348 This gives us a probability of approximately 0.4348 for a cloud cover of 6 or greater.

Step 2

find $P(X > 6)$

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Answer

Using the binomial distribution, we find:

P(X>6)=1P(X6)P(X > 6) = 1 - P(X \leq 6) To find P(X6)P(X \leq 6), we calculate:

P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) Using the binomial formula, where n=8n=8 and p=0.76p=0.76:

P(X=k)=(nk)pk(1p)nkP(X = k) = \binom{n}{k} p^k (1-p)^{n-k} Calculating these probabilities gives:

P(X>6)0.703P(X > 6) \approx 0.703

Step 3

find, to 1 decimal place, the expected number of days in a sample of 184 days with a daily mean total cloud cover of 7

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Answer

The expected number of days with a total cloud cover of 7 can be calculated using:

E[X=7]=npE[X=7] = n \cdot p With n=184n = 184 and p=P(X=7)p = P(X=7); From earlier calculations, we can estimate P(X=7)0.281P(X=7) \approx 0.281. Thus,

E[X=7]=1840.28151.78451.8E[X=7] = 184 \cdot 0.281 \approx 51.784\approx 51.8

Step 4

Explain whether or not your answers to part (b) support the use of Magali's model.

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Answer

The probabilities obtained in part (b) show a significant difference between P(X6)P(X \geq 6) (approximately 0.4348) and the expected P(X=7)P(X=7) (approximately 0.281). This indicates that there is a greater likelihood of days with a higher cloud cover than predicted by the model, suggesting that Magali's binomial model may not be suitable.

Step 5

Comment on the proportion of these days when the daily mean total cloud cover was 6 or greater.

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Answer

Out of the 28 days, since all were those with a daily mean total cloud cover of 8, we can say:

Proportion=2828=1.0\text{Proportion} = \frac{28}{28} = 1.0 Thus, 100% of these days had a cloud cover of 6 or greater.

Step 6

Comment on Magali's model in light of your answer to part (d).

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Answer

Given that all sampled days had a cloud cover of 8, indicating a higher proportion of high cloud cover, this suggests that the model may not accurately reflect the observed data. Therefore, Magali's model, which assumes a binomial distribution, may not be suitable as it does not account for the observed frequency of higher cloud covers.

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