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An estate agent recorded the price per square metre, $p ext{ £} / m^2$, for 7 two-bedroom houses - Edexcel - A-Level Maths Statistics - Question 2 - 2015 - Paper 1

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An estate agent recorded the price per square metre, $p ext{ £} / m^2$, for 7 two-bedroom houses. He then coded the data using the coding $q = \frac{p - a}{b}$, wh... show full transcript

Worked Solution & Example Answer:An estate agent recorded the price per square metre, $p ext{ £} / m^2$, for 7 two-bedroom houses - Edexcel - A-Level Maths Statistics - Question 2 - 2015 - Paper 1

Step 1

Find the value of a and the value of b.

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Answer

To find the constants aa and bb from the coding equation q=pabq = \frac{p - a}{b}, we can use the values from the table:

  1. From p=1840p = 1840 and q=4.0q = 4.0:

    4=1840ab4 = \frac{1840 - a}{b}

    This implies:

    4b=1840a(Equation 1)4b = 1840 - a\quad \text{(Equation 1)}

  2. From p=1848p = 1848 and q=4.8q = 4.8:

    4.8=1848ab4.8 = \frac{1848 - a}{b}

    Thus:

    4.8b=1848a(Equation 2)4.8b = 1848 - a\quad \text{(Equation 2)}

  3. Now, let's solve the equations. Rearranging Equation 1 gives us:

    a=18404ba = 1840 - 4b

    Substituting in Equation 2:

    4.8b=1848(18404b)4.8b = 1848 - (1840 - 4b)

    This simplifies to:

    4.8b=18481840+4b4.8b = 1848 - 1840 + 4b

    4.8b4b=80.8b=8b=104.8b - 4b = 8\quad \Rightarrow \quad 0.8b = 8\quad \Rightarrow \quad b = 10

  4. Substituting b=10b = 10 back into Equation 1:

    a=18404(10)=184040=1800a = 1840 - 4(10) = 1840 - 40 = 1800

Thus, the values are:

a=1800a = 1800 b=10b = 10

Step 2

Calculate the product moment correlation coefficient between d and q.

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Answer

To calculate the product moment correlation coefficient, we use the formula:

r=n(dq)(d)(q)[nd2(d)2][nq2(q)2]r = \frac{n(\sum{dq}) - (\sum{d})(\sum{q})}{\sqrt{[n\sum{d^2} - (\sum{d})^2][n\sum{q^2} - (\sum{q})^2]}}

Given:

  • Sd=1.02S_d = 1.02
  • Swq=8.22S_w^q = 8.22
  • Sq=2.17S_q = -2.17

Assuming that the number of houses n=7n = 7, we can derive the necessary sums:

  1. Calculate d\sum{d}:

    • From Sd=1.02S_d = 1.02, we estimate: d=Sd×n=1.02×7=7.14\sum{d} = S_d \times n = 1.02 \times 7 = 7.14
  2. Calculate q\sum{q}:

    • Since Sq=2.17S_q = -2.17, we estimate: q=Sq×n=2.17×7=15.19\sum{q} = S_q \times n = -2.17 \times 7 = -15.19
  3. Then, r=7(dq)(7.14)(15.19)[7d2(7.14)2][7q2(15.19)2]r = \frac{7(\sum dq) - (7.14)(-15.19)}{\sqrt{[7\sum{d^2} - (7.14)^2][7\sum{q^2} - (-15.19)^2]}}

Thus, calculate to find: r0.749r \approx -0.749

This indicates a strong negative correlation.

Step 3

Write down the value of the product moment correlation coefficient between d and p.

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Answer

The value of the product moment correlation coefficient between dd and pp is given as 0.749-0.749.

Step 4

Suggest which house is most likely to be closer to a train station. Justify your answer.

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Answer

To determine which house, HH or JJ, is more likely to be closer to a train station, we analyze the prices and sizes.

  • House HH costs £156,400 and has a size of 78 m².
  • House JJ costs £172,900 and has a size of 95 m².

Given that a higher price per square metre may suggest a location closer to amenities such as a train station, we calculate the price per square metre for both houses:

  • For House HH:

Price per m²=156400782005.13\text{Price per m²} = \frac{156400}{78} \approx 2005.13

  • For House JJ:

Price per m²=172900951810.53\text{Price per m²} = \frac{172900}{95} \approx 1810.53

Since House HH has a higher price per square metre, it indicates that it is likely to be closer to the train station compared to House JJ. Thus, House HH is most likely to be closer to a train station.

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