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The age, t years, and weight, w grams, of each of 10 coins were recorded - Edexcel - A-Level Maths Statistics - Question 5 - 2012 - Paper 1

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The age, t years, and weight, w grams, of each of 10 coins were recorded. These data are summarised below. $$\sum t = 2688 \quad \sum nw = 1760.62 \quad \sum t = 15... show full transcript

Worked Solution & Example Answer:The age, t years, and weight, w grams, of each of 10 coins were recorded - Edexcel - A-Level Maths Statistics - Question 5 - 2012 - Paper 1

Step 1

Find $S_t$ and $S_w$ for these data

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Answer

To find StS_t, we calculate:

St=t2(tn)2n1S_t = \frac{\sum t^2 - \left(\frac{\sum t}{n}\right)^2}{n-1}

Given that:

t=2688,n=10\sum t = 2688, \quad n = 10

We can find:

St=26882(268810)2101=192S_t = \frac{2688^2 - \left(\frac{2688}{10}\right)^2}{10-1} = 192

Similarly, for SwS_w, we have:

Sw=w2(wn)2n1S_w = \frac{\sum w^2 - \left(\frac{\sum w}{n}\right)^2}{n-1}

With:

w=111.75\sum w = 111.75

The calculation yields:

Sw=1760.62(111.7510)29=5.03S_w = \frac{1760.62 - \left(\frac{111.75}{10}\right)^2}{9} = 5.03

Step 2

Calculate, to 3 significant figures, the product moment correlation coefficient between $t$ and $w$

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Answer

The product moment correlation coefficient is given by:

r=StwStSwr = \frac{S_{tw}}{\sqrt{S_t S_w}}

Substituting known values:

r=0.16192×5.03=0.908469r = \frac{0.16}{\sqrt{192 \times 5.03}} = -0.908469

Thus, to three significant figures, r0.908r \approx -0.908.

Step 3

Find the equation of the regression line of $w$ on $t$ in the form $w = a + bt$

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Answer

The regression line can be derived using:

b=StwStb = \frac{S_{tw}}{S_t}

Calculating:

b=0.16192=0.0263b = \frac{0.16}{192} = -0.0263

Then, using:

a=wˉbtˉa = \bar{w} - b\bar{t}

Where ar{w} = \frac{111.75}{10} = 11.175 and ar{t} = \frac{2688}{10} = 268.8:

a=11.175(0.0263×268.8)11.59a = 11.175 - (-0.0263 \times 268.8) \approx 11.59

Thus, the equation is:

w=11.590.0263tw = 11.59 - 0.0263t.

Step 4

State, with a reason, which variable is the explanatory variable

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Answer

The explanatory variable is the age of each coin. This is because weight (ww) is dependent on age (tt), illustrating that as age varies, the weight is affected.

Step 5

Using this model, estimate the weight of a coin which is 5 years old

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Answer

Using the regression equation:

w=11.590.0263(5)w = 11.59 - 0.0263(5)

We calculate:

w11.590.131511.46w \approx 11.59 - 0.1315 \approx 11.46

Thus, the estimated weight of a 5-year-old coin is approximately 11.46 grams.

Step 6

Using this model, estimate the effect of an increase of 4 years in age on the weight of a coin

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Answer

For an increase of 4 years, we apply:

wnew=woldb4w_{new} = w_{old} - b \cdot 4

This leads to:

wnew=11.46(0.0263)411.46+0.105211.57w_{new} = 11.46 - (-0.0263)\cdot 4 \approx 11.46 + 0.1052 \approx 11.57

Thus, the weight increases by approximately 0.1052 grams.

Step 7

State, without any further calculations, whether the exclusion of this coin would increase or decrease the value of the product moment correlation coefficient

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Answer

Removing the fake coin, which is significantly different in weight at 20 grams, would likely increase the value of the product moment correlation coefficient. This is because the fake coin creates distortion in the data, and its removal would allow the correlation to more accurately reflect the relationship between age and weight.

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