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On a particular day the height above sea level, $x$ metres, and the mid-day temperature, $y$°C, were recorded in 8 north European towns - Edexcel - A-Level Maths Statistics - Question 1 - 2011 - Paper 2

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On a particular day the height above sea level, $x$ metres, and the mid-day temperature, $y$°C, were recorded in 8 north European towns. These data are summarised be... show full transcript

Worked Solution & Example Answer:On a particular day the height above sea level, $x$ metres, and the mid-day temperature, $y$°C, were recorded in 8 north European towns - Edexcel - A-Level Maths Statistics - Question 1 - 2011 - Paper 2

Step 1

Find $S_{xy}$

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Answer

To find SxyS_{xy}, we can use the formula:

Sxy=xyxynS_{xy} = \sum xy - \frac{\sum x \sum y}{n}

Given the required sums:

  • (S_{xy} = -23.72625)
  • (\sum x = 181)
  • (n = 8)

We already have SxyS_{xy} from the data provided.

Step 2

Calculate, to 3 significant figures, the product moment correlation coefficient for these data.

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Answer

The formula for the product moment correlation coefficient, rr, is:

r=SxySxxSyyr = \frac{S_{xy}}{\sqrt{S_{xx} S_{yy}}}

Where:

  • Sxx=353.2375S_{xx} = 353.2375
  • Syy=4305(1812)8S_{yy} = 4305 - \frac{(181^2)}{8} (Calculate for SyyS_{yy})

Thus,

Syy=4305(1812)8=43054090.25=214.75S_{yy} = 4305 - \frac{(181^2)}{8} = 4305 - 4090.25 = 214.75

Finally, substituting into the correlation formula gives: r=23.72625353.2375214.75=0.87104r = \frac{-23.72625}{\sqrt{353.2375 * 214.75}} = -0.87104

To 3 significant figures, this results in: r0.871r \approx -0.871

Step 3

Give an interpretation of your coefficient.

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Answer

The correlation coefficient of r=0.871r = -0.871 indicates a strong negative correlation between the height above sea level and the mid-day temperature. This implies that, generally, as the height increases, the temperature tends to decrease.

Step 4

Write down the value of $S_{hh}$

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Answer

To find ShhS_{hh}, we need to apply the transformation of the variable:

h=x1000h = \frac{x}{1000}

Thus,

Shh=Sxx×(110002)=353.2375×11000000=0.0003532375S_{hh} = S_{xx} \times \left(\frac{1}{1000^2}\right) = 353.2375 \times \frac{1}{1000000} = 0.0003532375

Step 5

Write down the value of the correlation coefficient between $h$ and $y$.

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Answer

Since hh is a linear transformation of xx, the correlation coefficient between hh and yy remains the same. Therefore, the correlation coefficient between hh and yy is:

r=0.871r = -0.871

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