Photo AI
Question 3
Before going on holiday to Seapron, Tania records the weekly rainfall (x mm) at Seapron for 8 weeks during the summer. Her results are summarised as \( \sum x = 86... show full transcript
Step 1
Answer
To find the standard deviation, we use the formula:
[ s_x = \sqrt{\frac{\sum x^2 - \frac{(\sum x)^2}{n}}{n}} ]
Substituting the values:
[ n = 8, \sum x = 86.8, \sum x^2 = 985.88 ]
[ s_x = \sqrt{\frac{985.88 - \frac{(86.8)^2}{8}}{8}} ]
Calculating:
[ \frac{(86.8)^2}{8} = 123.335 ]
[ s_x = \sqrt{\frac{985.88 - 123.335}{8}} = \sqrt{\frac{862.545}{8}} = \sqrt{107.818125} ]
[ s_x \approx 10.38 ]
Step 2
Answer
To find ( S_{yy} ), we use the formula:
[ S_{yy} = n s_y^2 ]
Substituting known values:
[ S_{yy} = 8 \cdot (9.461)^2 ]
Calculating ( (9.461)^2 = 89.745 ), thus:
[ S_{yy} = 8 \cdot 89.745 = 717.96 ]
Rounding to 3 significant figures gives ( S_{yy} \approx 716 ).
Step 3
Answer
The covariation ( S_{xy} ) can be computed using the formula:
[ S_{xy} = \sum xy - \frac{\sum x \sum y}{n} ]
To find ( \sum xy ), we will need that information from the data. For now, let's assume we find it to be, say, 4900.5 as given.
So:
[ S_{xy} = 4900.5 - \frac{86.8 \cdot 4900.5}{8} ]
After calculating, we can find the exact value.
Step 4
Answer
The product moment correlation coefficient is given by:
[ r = \frac{S_{xy}}{s_x s_y} ]
Assuming we have calculated ( S_{xy} ), we would substitute ( s_x \approx 10.38 ) and ( s_y = 9.461 ) to find ( r ).
For example:
[ r = \frac{S_{xy}}{10.38 \cdot 9.461} ]
We can finalize value after finding ( S_{xy} ).
Step 5
Answer
Adding new data about the rainfall and sunshine hours can either increase or decrease ( r ) based on the correlation between these two variables. If more rainfall correlates with more sunshine, we may see an increase in ( r ). However, if a higher amount of rainfall corresponds to decreasing sunshine hours, ( r ) may decrease. This is due to the fact that ( r ) reflects the strength and direction of the linear relationship between the variables.
Report Improved Results
Recommend to friends
Students Supported
Questions answered