For the events A and B,
P(A ∩ B') = 0.32, P(A' ∩ B) = 0.11 and P(A ∪ B) = 0.65 - Edexcel - A-Level Maths Statistics - Question 6 - 2006 - Paper 1
Question 6
For the events A and B,
P(A ∩ B') = 0.32, P(A' ∩ B) = 0.11 and P(A ∪ B) = 0.65.
(a) Draw a Venn diagram to illustrate the complete sample space for the events A an... show full transcript
Worked Solution & Example Answer:For the events A and B,
P(A ∩ B') = 0.32, P(A' ∩ B) = 0.11 and P(A ∪ B) = 0.65 - Edexcel - A-Level Maths Statistics - Question 6 - 2006 - Paper 1
Step 1
Draw a Venn diagram to illustrate the complete sample space for the events A and B.
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Answer
To draw the Venn diagram, we represent events A and B as two overlapping circles within a rectangle which represents the sample space E.
The area for A only is represented as P(A) - P(A ∩ B).
The area for B only is represented as P(B) - P(A ∩ B).
The area where A and B overlap is P(A ∩ B).
The area outside both A and B is represented by the remaining portion of E.
Using the provided probabilities:
P(A ∩ B) = 0.32 + 0.11 + 0.35 = 0.54
P(A) + P(B) + P(A ∩ B) = 1
P(A ∪ B) = 0.65
Calculating further, we find:
P(A) = 0.32 + 0.22 = 0.54
P(B) = 0.11 + 0.22 = 0.33
Thus the complete diagram will show:
A: 0.32
B: 0.11
A ∩ B: 0.22
Outside (E): 0.35.
Step 2
Write down the value of P(A) and the value of P(B).
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Answer
From the calculations in part (a), we find:
P(A) = 0.54
P(B) = 0.33.
Step 3
Find P(A | B').
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Answer
To find P(A | B'), use the conditional probability formula:
P(A∣B′)=P(B′)P(A∩B′)
We know:
P(A ∩ B') = 0.32
P(B') = 1 - P(B) = 1 - 0.33 = 0.67
So,
P(A∣B′)=0.670.32≈0.478
Step 4
Determine whether or not A and B are independent.
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Answer
To determine independence, we check if:
P(A∩B)=P(A)×P(B)
Using our values:
P(A ∩ B) = 0.22
P(A) = 0.54
P(B) = 0.33
Calculating:
P(A)×P(B)=0.54×0.33=0.1782
Since P(A∩B)=P(A)×P(B), we conclude that A and B are NOT independent.