Photo AI

The discrete random variable X has the following probability distribution, where p and q are constants - Edexcel - A-Level Maths Statistics - Question 2 - 2016 - Paper 1

Question icon

Question 2

The-discrete-random-variable-X-has-the-following-probability-distribution,-where-p-and-q-are-constants-Edexcel-A-Level Maths Statistics-Question 2-2016-Paper 1.png

The discrete random variable X has the following probability distribution, where p and q are constants. | x | -2 | -1 | 1/2 | 3/2 | 2 | | P(X = x) | p | q | 0.2 | 0... show full transcript

Worked Solution & Example Answer:The discrete random variable X has the following probability distribution, where p and q are constants - Edexcel - A-Level Maths Statistics - Question 2 - 2016 - Paper 1

Step 1

Write down an equation in p and q

96%

114 rated

Answer

Since the total probability must equal 1, we have the equation:

p+q+0.2+0.3+p=1p + q + 0.2 + 0.3 + p = 1

This simplifies to: 2p+q+0.5=12p + q + 0.5 = 1

Thus, 2p+q=0.52p + q = 0.5

Step 2

find the value of q

99%

104 rated

Answer

We know that E(X)=2pq0.5+1.5p+2pE(X) = -2p - q - 0.5 + 1.5p + 2p Substituting E(X) = 0.4, we get:

\Rightarrow -p - q + 1.5 = 0.4\ \Rightarrow -p - q = -1.1\ \Rightarrow p + q = 1.1$$ Now we have two equations: 1. $$2p + q = 0.5$$ 2. $$p + q = 1.1$$ Subtracting these two equations: $$p = 0.15\ \Rightarrow q = 1.1 - 0.15 = 0.95$$

Step 3

hence find the value of p

96%

101 rated

Answer

Using the value of q found in the previous step, we substitute back into the first equation:

\Rightarrow 2p = 0.5 - 0.95 = -0.45\ \Rightarrow p = -0.225$$

Step 4

find Var(X)

98%

120 rated

Answer

Using the given value for E(X^2) = 2.275, we can find Var(X) as:

Var(X) = 2.275 - (0.4)^2 = 2.275 - 0.16 = 2.115$$

Step 5

Find E(R)

97%

117 rated

Answer

The expectation E(R) can be computed as follows:

E(R)=E(1X)=P(X=2)12+P(X=1)11+P(X=0.5)2+P(X=1.5)23+P(X=2)12E(R) = E\left(\frac{1}{X}\right) = P(X = -2) * \frac{1}{-2} + P(X = -1) * \frac{1}{-1} + P(X = 0.5) * 2 + P(X = 1.5) * \frac{2}{3} + P(X = 2) * \frac{1}{2} Substituting, we get:

=p(12)+q(1)+0.2(2)+0.3(23)+p(12)= p(-\frac{1}{2}) + q(-1) + 0.2(2) + 0.3(\frac{2}{3}) + p(\frac{1}{2}) Substituting p and q, we find:

E(R)=0.1520.95+0.4+0.2+0.075=0.45E(R) = -\frac{0.15}{2} - 0.95 + 0.4 + 0.2 + 0.075 = 0.45

Step 6

Find the probability that Sarah is the winner

97%

121 rated

Answer

The probability that Sarah wins can be computed using the given values of X:

= P(S > \frac{1}{X})$$ We can integrate over all values of X based on the distribution of X to calculate this probability.

Step 7

Find the probability that Rebecca is the winner

96%

114 rated

Answer

The probability that Rebecca wins can be calculated similarly:

= P(\frac{1}{X} > X)$$ Again, we integrate over the distribution of X to find this.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;