Photo AI

Over a long period of time a small company recorded the amount it received in sales per month - Edexcel - A-Level Maths Statistics - Question 3 - 2011 - Paper 1

Question icon

Question 3

Over-a-long-period-of-time-a-small-company-recorded-the-amount-it-received-in-sales-per-month-Edexcel-A-Level Maths Statistics-Question 3-2011-Paper 1.png

Over a long period of time a small company recorded the amount it received in sales per month. The results are summarised below. | Amount received in sales (£1000s)... show full transcript

Worked Solution & Example Answer:Over a long period of time a small company recorded the amount it received in sales per month - Edexcel - A-Level Maths Statistics - Question 3 - 2011 - Paper 1

Step 1

Draw a Box Plot and Identify Outliers

96%

114 rated

Answer

To construct the box plot, we first determine the necessary components:

  • Lower Quartile (Q1): 7
  • Median (Q2): 12
  • Upper Quartile (Q3): 14

Next, calculate the interquartile range (IQR):

IQR=Q3Q1=147=7IQR = Q3 - Q1 = 14 - 7 = 7

Now, calculate the lower and upper outlier limits:

  • Lower outlier limit = Q1 - 1.5 × IQR = 7 - 1.5 × 7 = -3.5
  • Upper outlier limit = Q3 + 1.5 × IQR = 14 + 1.5 × 7 = 24.5

Since 25 (the highest value) exceeds the upper limit (24.5), it qualifies as an outlier.

The box plot will display the following:

  • A box from Q1 (7) to Q3 (14).
  • A line at the median (12).
  • Whiskers extending to the two lowest values (3 and 4) and to the upper limit (20).
  • An isolated point representing the outlier (25).

Indicate the outlier clearly on the diagram.

Step 2

State the Skewness of the Distribution

99%

104 rated

Answer

The skewness of a distribution can be assessed using the relative differences between the quartiles. Since:

Q3Q2<Q2Q1Q3 - Q2 < Q2 - Q1

which translates to:

1412<12714 - 12 < 12 - 7

This confirms that the data is negatively skewed. In a negatively skewed distribution, the left tail (lower values) is longer or fatter than the right tail, thus our conclusion is that the distribution has a negative skew.

Step 3

Comment on the Claim about Sales

96%

101 rated

Answer

The company claims that for 75% of the months, the amount received per month is greater than £10000. To evaluate this, we look at the quartile data. The lower quartile (Q1) is 7, indicating that 25% of the months had sales below £7000. Therefore, it can be concluded that:

  • Since the median (Q2) is 12 (representing £12000), and also considering the upper limit of sales, it suggests that only 50% of the observed data lies above £10000.
  • Consequently, 75% of the months cannot possibly exceed the claim of receiving more than £10000. Thus, the company's claim is not true.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;