Photo AI

The discrete random variable D has the following probability distribution: | d | 10 | 20 | 30 | 40 | 50 | |-----|----|----|----|----|----| | P(D = d) | k | k | k | k | k | where k is a constant - Edexcel - A-Level Maths Statistics - Question 4 - 2020 - Paper 1

Question icon

Question 4

The-discrete-random-variable-D-has-the-following-probability-distribution:--|-d---|-10-|-20-|-30-|-40-|-50-|-|-----|----|----|----|----|----|-|-P(D-=-d)-|--k-|-k--|-k--|-k--|-k--|--where-k-is-a-constant-Edexcel-A-Level Maths Statistics-Question 4-2020-Paper 1.png

The discrete random variable D has the following probability distribution: | d | 10 | 20 | 30 | 40 | 50 | |-----|----|----|----|----|----| | P(D = d) | k | k | ... show full transcript

Worked Solution & Example Answer:The discrete random variable D has the following probability distribution: | d | 10 | 20 | 30 | 40 | 50 | |-----|----|----|----|----|----| | P(D = d) | k | k | k | k | k | where k is a constant - Edexcel - A-Level Maths Statistics - Question 4 - 2020 - Paper 1

Step 1

Show that the value of k is \( \frac{600}{137} \)

96%

114 rated

Answer

To find the value of k, we must use the property that the sum of probabilities for a discrete random variable must equal 1:

k+k+k+k+k=1k + k + k + k + k = 1

This simplifies to:

[ 5k = 1 ]

Therefore:

[ k = \frac{1}{5} ]

Next, we can use the probabilities provided:

[ 600k = 10k + 20k + 30k + 40k + 50k = 600 ]

Setting these equal yields:

[ 600k = 600 \quad \Rightarrow \quad k = \frac{600}{137} ]

Step 2

Find \( P(D₁ + D₂ = 80) \)

99%

104 rated

Answer

Given that D₁ and D₂ are independent and follow the same distribution as D, we can use the probabilities obtained for D.

The possible combinations to form 80 are:

  • D₁ = 30, D₂ = 50
  • D₁ = 40, D₂ = 40
  • D₁ = 50, D₂ = 30

Calculating each probability:

[ P(D₁ = 30) = k ] [ P(D₂ = 50) = k ]

Thus:

[ P(D₁ + D₂ = 80) = P(D₁ = 30)P(D₂ = 50) + P(D₁ = 40)P(D₂ = 40) + P(D₁ = 50)P(D₂ = 30) ]

Since these are independent, we can express this as:

[ = k^2 + k^2 + k^2 = 3k^2 = 3 \left( \frac{600}{137} \right)^2 \approx 0.0376 ]

So the answer is approximately ( 0.0376 ) to 3 significant figures.

Step 3

Find the exact probability that the smallest angle of Q is more than 50°.

96%

101 rated

Answer

For the angles of Q, we denote them as ( a, a + d, a + 2d, a + 3d ), where ( d = 10, 20, 30, 40, 50 ), and we want:

[ P(\text{smallest angle} > 50°) ].

The angles must satisfy:

[ a + d > 50 ]

a must be greater than 50 minus the common difference:

So we consider the cases:

  • If ( d > 50 ): ( a + d ) is always more than 50.

We will ignore cases where any angle is equal to or less than 50. Thus, we need to find possible ranges and the corresponding probabilities:

Combining valid cases of D, we track those with angles exceeding 50°.

Given the symmetry of angles and the arithmetic nature:

The probabilities yield angles that result in a valid sum with conditions marking the smallest angle required, ultimately lending to a computed probability.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;