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A 2-beam oscilloscope is used to determine the speed of sound in air - Edexcel - A-Level Physics - Question 3 - 2023 - Paper 2

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A 2-beam oscilloscope is used to determine the speed of sound in air. The oscilloscope screen shown displays the signal used to produce the sound wave. The time-bas... show full transcript

Worked Solution & Example Answer:A 2-beam oscilloscope is used to determine the speed of sound in air - Edexcel - A-Level Physics - Question 3 - 2023 - Paper 2

Step 1

Determine the Period from the Oscilloscope Signal

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Answer

To find the frequency, we first need to determine the period of the wave displayed on the oscilloscope. The given time base is set at 50 μs per division. We count the number of divisions that one complete wave takes. Assuming it takes 4 divisions to complete one wave:

extPeriod=4 divisions×50μs/division=200μs=200×106s ext{Period} = 4 \text{ divisions} \times 50 \mu s/{\text{division}} = 200 \mu s = 200 \times 10^{-6} s

Step 2

Calculate Frequency using the Period

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Frequency ( ) is the reciprocal of the period (T):

f=1Tf = \frac{1}{T}

Substituting the value of the period:

f=1200×106=5000Hzf = \frac{1}{200 \times 10^{-6}} = 5000 Hz.

Step 3

Determine the Correct Answer Option

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Finally, we check the calculated frequency against the options provided:

  • A: 5×50×1065 \times 50 \times 10^{-6} = 0.00025 Hz
  • B: 2.5×50×1062.5 \times 50 \times 10^{-6} = 0.000125 Hz
  • C: 11 = 1 Hz
  • D: 2.5×5×1062.5 \times 5 \times 10^{-6} = 0.0000125 Hz

The correct interpretation leads to the conclusion that option C (1 Hz) does not match the calculated frequency, therefore option C must not be correct based on our calculations. The frequency calculated appears valid and thus the expected option can be adjusted if further details from the marking scheme were to allow such alterations.

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