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A student investigated the stretching of a spring - Edexcel - A-Level Physics - Question 3 - 2023 - Paper 3

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A student investigated the stretching of a spring. (a) The student used a metre rule to measure the unstretched length l0 of the spring. (i) The value of l0 was 5.... show full transcript

Worked Solution & Example Answer:A student investigated the stretching of a spring - Edexcel - A-Level Physics - Question 3 - 2023 - Paper 3

Step 1

Explain why a metre rule is an appropriate instrument for this measurement.

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Answer

A metre rule is appropriate for measuring the unstretched length of the spring because:

  1. Precision: It allows for precise measurement, typically down to 0.1 cm, which is suitable for this scale of measurement.
  2. Visibility: The markings on the rule are clear and easy to read, enabling accurate readings without much parallax error.

Step 2

Describe two techniques the student should use to make this measurement as accurate as possible.

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Answer

  1. Ensure the rule is vertical: The student should make sure the ruler is vertical relative to the spring to minimize any measurement errors caused by angle misalignment.

  2. Use a set square: The use of a set square to hold the ruler in place can prevent it from moving, ensuring that the position of the spring is stable when taking the measurement.

Step 3

Criticise the recording of these results.

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Answer

The recording of results can be criticized due to:

  • Missing Data Points: The weight of 0.39 N corresponds to a stretched length of 12 cm, which shows a significant jump in values without intermediate measurements that could provide more data points for analysis.

Step 4

Explain which value he should check.

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Answer

The student should check the value at W = 0.39 N for consistency with the linear relationship shown in the graph, as it is an outlier compared to other points nearer to the line of best fit.

Step 5

Determine the weight W of the piece of modelling clay.

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Answer

To find the weight W of the piece of modelling clay, we can use the formula:

W=kimes(ll0)W = k imes (l - l_0)

Where k is the spring constant. Here, using the information provided, we can deduce that the stretching due to modelling clay leads to:

W=0.39N+0.05N=0.44NW = 0.39 N + 0.05 N = 0.44 N

Step 6

Determine the density of the modelling clay.

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Answer

Using the formula given for density:

density of modelling clay=WfWfF\text{density of modelling clay} = \frac{W_f}{W_f - F}

Substituting the values, we get:

density of modelling clay=0.650.650.27=0.650.381710 kg/m3\text{density of modelling clay} = \frac{0.65}{0.65 - 0.27} = \frac{0.65}{0.38} \approx 1710 \text{ kg/m}^3

Step 7

Deduce whether the modelling clay could be made from polymer clay.

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Answer

Considering the density calculated as approximately 1710 kg/m³:

  • The density of polymer clay is provided as 1760 kg/m³, and since 1710 kg/m³ is less than this density and within a 4% uncertainty range, it is reasonable to conclude that the modelling clay could potentially be made from polymer clay.

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