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The circuit shown provides an input to a transistor: A transistor is a type of electronic switch and in this circuit it can be assumed to have infinite resistance; 7.0 V The resistance of the LDR varies with light level as shown below - Edexcel - A-Level Physics - Question 13 - 2023 - Paper 1

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Question 13

The-circuit-shown-provides-an-input-to-a-transistor:-A-transistor-is-a-type-of-electronic-switch-and-in-this-circuit-it-can-be-assumed-to-have-infinite-resistance;--7.0-V--The-resistance-of-the-LDR-varies-with-light-level-as-shown-below-Edexcel-A-Level Physics-Question 13-2023-Paper 1.png

The circuit shown provides an input to a transistor: A transistor is a type of electronic switch and in this circuit it can be assumed to have infinite resistance; ... show full transcript

Worked Solution & Example Answer:The circuit shown provides an input to a transistor: A transistor is a type of electronic switch and in this circuit it can be assumed to have infinite resistance; 7.0 V The resistance of the LDR varies with light level as shown below - Edexcel - A-Level Physics - Question 13 - 2023 - Paper 1

Step 1

30 lux corresponds to 3000 Ω

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Answer

To determine the resistance of the Light Dependent Resistor (LDR) at 30 lux, we can refer to the graph provided. The graph indicates that when the light level is at 30 lux, the corresponding resistance is approximately 3000 Ω.

Next, we will calculate the potential difference across the LDR.

Using the voltage divider rule, we have:

V=7.0×RLDRRLDR+333V = 7.0 \times \frac{R_{LDR}}{R_{LDR} + 333}

Substituting the values:

V=7.0×30003000+333=7.0×300033336.3VV = 7.0 \times \frac{3000}{3000 + 333} = 7.0 \times \frac{3000}{3333} \approx 6.3 V

The potential difference across the LDR is approximately 6.3 V, which is above the 0.7 V threshold necessary for the transistor to turn on.

Step 2

So p.d. to transistor increases so does perform as required

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Answer

As the light level increases and the resistance of the LDR decreases, the potential difference across the transistor increases accordingly. This behavior follows from the earlier calculation.

If the resistance continues to decrease as light levels rise, the total p.d. across the input will also increase, enabling the transistor to conduct effectively and perform its function as an electronic switch.

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