The circuit shows a 1 mF capacitor connected to an a.c - Edexcel - A-Level Physics - Question 18 - 2023 - Paper 1
Question 18
The circuit shows a 1 mF capacitor connected to an a.c. supply. The graph shows how the potential difference V varies with time t.
(a) (i) Calculate the root-mean-s... show full transcript
Worked Solution & Example Answer:The circuit shows a 1 mF capacitor connected to an a.c - Edexcel - A-Level Physics - Question 18 - 2023 - Paper 1
Step 1
Calculate the root-mean-square potential difference
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Answer
The root-mean-square (RMS) potential difference for an alternating current (AC) waveform can be calculated using the formula:
Vrms=2Vmax
In this case, the maximum potential difference, Vmax, can be identified from the equation ( V = 5 \sin(100\pi t) ), where Vmax=5V. Thus:
Vrms=25≈3.54 V
Step 2
Explain why this formula leads to the graph above
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Answer
The formula ( V = 5\sin(100\pi t) ) represents a sinusoidal waveform, which is characteristic of alternating current. The sine function oscillates between -5V and +5V, resulting in a repetitive smooth wave shape.
Amplitude: The amplitude of the wave (5V) indicates the maximum potential difference reached at peaks.
Frequency: The term ( 100\pi ) corresponds to the frequency of the wave, affecting how fast it completes one cycle. The period of the waveform can be derived from the angular frequency as:
T=100π2π=0.02s
This explains the horizontal periodicity as observed in the graph. Each cycle of this wave corresponds to a rise and fall in the potential difference, which is depicted in the provided graph.