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The circuit shows a 1 mF capacitor connected to an a.c - Edexcel - A-Level Physics - Question 18 - 2023 - Paper 1

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The circuit shows a 1 mF capacitor connected to an a.c. supply. The graph shows how the potential difference V varies with time t. (a) (i) Calculate the root-mean-s... show full transcript

Worked Solution & Example Answer:The circuit shows a 1 mF capacitor connected to an a.c - Edexcel - A-Level Physics - Question 18 - 2023 - Paper 1

Step 1

Calculate the root-mean-square potential difference

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Answer

The root-mean-square (RMS) potential difference for an alternating current (AC) waveform can be calculated using the formula:

Vrms=Vmax2V_{rms} = \frac{V_{max}}{\sqrt{2}}

In this case, the maximum potential difference, VmaxV_{max}, can be identified from the equation ( V = 5 \sin(100\pi t) ), where Vmax=5VV_{max} = 5V. Thus:

Vrms=523.54 VV_{rms} = \frac{5}{\sqrt{2}} \approx 3.54 \text{ V}

Step 2

Explain why this formula leads to the graph above

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Answer

The formula ( V = 5\sin(100\pi t) ) represents a sinusoidal waveform, which is characteristic of alternating current. The sine function oscillates between -5V and +5V, resulting in a repetitive smooth wave shape.

  • Amplitude: The amplitude of the wave (5V) indicates the maximum potential difference reached at peaks.
  • Frequency: The term ( 100\pi ) corresponds to the frequency of the wave, affecting how fast it completes one cycle. The period of the waveform can be derived from the angular frequency as:

T=2π100π=0.02sT = \frac{2\pi}{100\pi} = 0.02 \, s

This explains the horizontal periodicity as observed in the graph. Each cycle of this wave corresponds to a rise and fall in the potential difference, which is depicted in the provided graph.

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