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A motor lifts a mass of 50000 kg through a vertical height of 25 m - Edexcel - A-Level Physics - Question 8 - 2023 - Paper 1

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A motor lifts a mass of 50000 kg through a vertical height of 25 m. The motor has an output power of 700 kW. Which of the following gives the time in seconds taken t... show full transcript

Worked Solution & Example Answer:A motor lifts a mass of 50000 kg through a vertical height of 25 m - Edexcel - A-Level Physics - Question 8 - 2023 - Paper 1

Step 1

Calculate the gravitational potential energy (GPE)

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Answer

The gravitational potential energy is given by the formula:

GPE=mghGPE = mgh

where:

  • m=50000kgm = 50000 \, kg (mass)
  • g=9.81m/s2g = 9.81 \, m/s^2 (acceleration due to gravity)
  • h=25mh = 25 \, m (height)

Substituting the values:

GPE=50000kg×9.81m/s2×25m=12262500JGPE = 50000 \, kg \times 9.81 \, m/s^2 \times 25 \, m = 12262500 \, J.

Thus, the GPE required to lift the mass is 12262500 J.

Step 2

Calculate the time taken to lift the mass

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Answer

The power of the motor is given as 700 kW, which is equivalent to:

P=700×103WP = 700 \times 10^3 \, W

Using the formula for power, defined as work done over time:

P=WtP = \frac{W}{t},

we can rearrange this to solve for time tt:

t=WPt = \frac{W}{P}.

Substituting the work done (which is equal to GPE) and the power:

t=12262500J700×103W=17.5secondst = \frac{12262500 \, J}{700 \times 10^3 \, W} = 17.5 \, seconds.

Thus, the time taken to lift the mass can be found from the options provided.

Step 3

Identify the correct answer from the options

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Answer

From the calculations, we see that the correct answer corresponds to the formula used for GPE in option B:

50000×9.81×25700000\frac{50000 \times 9.81 \times 25}{700000},

which, when calculated, yields the time taken in seconds.

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