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Overhead electricity cables for railway lines are supported by structures like the one shown - Edexcel - A-Level Physics - Question 14 - 2023 - Paper 1

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Overhead electricity cables for railway lines are supported by structures like the one shown. An electric cable of mass 45 kg is suspended from a support rod X. A s... show full transcript

Worked Solution & Example Answer:Overhead electricity cables for railway lines are supported by structures like the one shown - Edexcel - A-Level Physics - Question 14 - 2023 - Paper 1

Step 1

Determine the forces and distances

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Answer

Let the weight of the cable be calculated first:

Weight (W) = mass × g = 45 kg × 9.8 m/s² = 441 N.

Next, identify the distance from the pivot point (the point where rod X meets the column) to where the force is applied. Here, the distance from X to the center of the cable is 1.5 m, and the angle θ = 35°.

Step 2

Set up the moment equation

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Answer

Taking moments about point X, we consider the clockwise moments due to the weight of the cable and the counterclockwise moment due to the force from rod Y (let's denote it as F_Y).

The moment due to the weight of the cable:

Moment_W = W * distance = 441 N * 1.5 m * cos(35°).

The moment due to the force from rod Y:

Moment_Y = F_Y * 1.3 m.

Step 3

Equate the moments

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Answer

Setting the clockwise moments equal to the counterclockwise moments:

441imes1.5imesextcos(35°)=FYimes1.3441 imes 1.5 imes ext{cos}(35°) = F_Y imes 1.3

From this equation, we can solve for F_Y.

Step 4

Solve for F_Y

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Answer

Calculate the left hand side:

441imes1.5imesextcos(35°)=441imes1.5imes0.819=543.3N.441 imes 1.5 imes ext{cos}(35°) = 441 imes 1.5 imes 0.819 = 543.3 N.

Now substituting back to find F_Y:

543.3=FYimes1.3FY=543.31.3418.69extN.543.3 = F_Y imes 1.3 \Rightarrow F_Y = \frac{543.3}{1.3} \approx 418.69 ext{ N}.

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