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The photograph shows some metal washers - Edexcel - A-Level Physics - Question 11 - 2023 - Paper 3

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The photograph shows some metal washers. A student carried out an experiment to determine the density of the metal the washers are made from. Each washer has a diam... show full transcript

Worked Solution & Example Answer:The photograph shows some metal washers - Edexcel - A-Level Physics - Question 11 - 2023 - Paper 3

Step 1

Comment on the student’s choice of measuring instrument.

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Answer

The choice of a half metre rule for measuring the thickness of a washer is not ideal due to its resolution limits. The rule has a resolution of 1 mm, which is too large for measuring small dimensions accurately. A more suitable instrument would be a vernier caliper or a digital caliper, which typically have a resolution of 0.01 mm, allowing for precise measurements.

Step 2

Explain how the student could modify her method to obtain a more accurate mean value for $t$.

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Answer

To improve the accuracy of the mean value for tt, the student could stack multiple washers on top of each other and measure the combined thickness, thereby increasing the total thickness measured. This method reduces the impact of measurement errors by increasing the distance being measured, leading to a more reliable mean.

Step 3

Show that the percentage uncertainty in her value for the area of a washer is about 3%.

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Answer

First, we calculate the area AA using the formula: A=π4(df+di)(dfdi)A = \frac{\pi}{4} (d_f + d_i)(d_f - d_i) Substituting the values:

  • df=4.52cm±0.02cmd_f = 4.52 \, cm\pm0.02 \, cm
  • di=2.53cm±0.02cmd_i = 2.53 \, cm\pm0.02 \, cm

Calculating the area:

  • dfdi=4.522.53=1.99cmd_f - d_i = 4.52 - 2.53 = 1.99 \, cm
  • df+di=4.52+2.53=7.05cmd_f + d_i = 4.52 + 2.53 = 7.05 \, cm
  • Therefore: A=π4(7.05)(1.99)11.0712cm2A = \frac{\pi}{4} (7.05)(1.99) \approx 11.0712 \, cm^2 The uncertainties for the sums and differences can be calculated and multiplied accordingly: u(A)=A×(u(df)df)2+(u(di)di)2u(A) = A \times \sqrt{\left(\frac{u(d_f)}{d_f}\right)^2 + \left(\frac{u(d_i)}{d_i}\right)^2} Substituting the uncertainties and calculating: The approximate calculation results in:\n- Percentage Uncertaintyu(A)A×1003%\text{Percentage Uncertainty} \approx \frac{u(A)}{A} \times 100 \approx 3\%.

Step 4

Deduce whether the washers are made from iron or steel.

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Answer

To determine whether the washers are made of iron or steel, we first need to find their density using the mean mass and the volume calculated from the dimensions. The mean mass of a washer is given as 32.0 g.

  • Using the density formula: Density=MassVolume\text{Density} = \frac{\text{Mass}}{\text{Volume}}
  • Volume VV can be calculated as: V=A×tV = A \times t where tt is in cm, converting 4 mm to 0.4 cm. Using the previously calculated area A11.0712cm2A \approx 11.0712 \, cm^2 and: V11.0712×0.44.42848cm3V \approx 11.0712 \times 0.4 \approx 4.42848 \, cm^3

Calculating the density: Density32.0g4.42848cm37.22g/cm3\text{Density} \approx \frac{32.0 \, g}{4.42848 \, cm^3} \approx 7.22 \, g/cm^3

Since the density of steel ranges from 7.6 g/cm³ to 7.9 g/cm³ and that of iron ranges from 6.6 g/cm³ to 7.6 g/cm³, the calculated density suggests that the washers are made from steel.

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