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How much more milk would a typical adult have to drink to get their RDA for calcium compared with the amount of milk needed to get their RDA for vitamin B-12? ================================== For calcium, the RDA is 1000 mg - AQA - GCSE Biology - Question 7 - 2018 - Paper 1

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How-much-more-milk-would-a-typical-adult-have-to-drink-to-get-their-RDA-for-calcium-compared-with-the-amount-of-milk-needed-to-get-their-RDA-for-vitamin-B-12?-----==================================-----For-calcium,-the-RDA-is-1000-mg-AQA-GCSE Biology-Question 7-2018-Paper 1.png

How much more milk would a typical adult have to drink to get their RDA for calcium compared with the amount of milk needed to get their RDA for vitamin B-12? ==... show full transcript

Worked Solution & Example Answer:How much more milk would a typical adult have to drink to get their RDA for calcium compared with the amount of milk needed to get their RDA for vitamin B-12? ================================== For calcium, the RDA is 1000 mg - AQA - GCSE Biology - Question 7 - 2018 - Paper 1

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How much more milk would a typical adult have to drink to get their RDA for calcium compared with the amount of milk needed to get their RDA for vitamin B-12?

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Answer

  1. Calculate the volume of milk needed for calcium:

    • RDA for calcium: 1000 mg
    • From Table 8: 500 cm³ of milk contains 605 mg of calcium.

    Volume of milk for calcium=1000 mg605 mg per 500 cm3×500 cm3=826.4 cm3\text{Volume of milk for calcium} = \frac{1000\text{ mg}}{605\text{ mg per } 500\text{ cm}^{3}} \times 500\text{ cm}^{3} = 826.4\text{ cm}^{3}

  2. Calculate the volume of milk needed for Vitamin B-12:

    • RDA for vitamin B-12: 2.4 µg
    • From Table 8: 500 cm³ of milk contains 4.5 µg.

    Volume of milk for vitamin B-12=2.4μg4.5μg×500 cm3=266.67 cm3\text{Volume of milk for vitamin B-12} = \frac{2.4\mu g}{4.5\mu g} \times 500\text{ cm}^{3} = 266.67\text{ cm}^{3}

  3. Calculate the extra volume of milk required for calcium:

    • Difference=826.4 cm3266.67 cm3=559.73 cm3\text{Difference} = 826.4\text{ cm}^{3} - 266.67\text{ cm}^{3} = 559.73\text{ cm}^{3}

Thus, a typical adult would need to drink approximately 559.73 cm³ more milk to meet the calcium RDA.

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