Photo AI

A student investigated the colours in a brown ink using chromatography - AQA - GCSE Chemistry Combined Science - Question 1 - 2022 - Paper 2

Question icon

Question 1

A-student-investigated-the-colours-in-a-brown-ink-using-chromatography-AQA-GCSE Chemistry Combined Science-Question 1-2022-Paper 2.png

A student investigated the colours in a brown ink using chromatography. Figure 1 shows the apparatus used. Give two errors made by the student. Describe the probl... show full transcript

Worked Solution & Example Answer:A student investigated the colours in a brown ink using chromatography - AQA - GCSE Chemistry Combined Science - Question 1 - 2022 - Paper 2

Step 1

Give two errors made by the student. Describe the problem each error would cause.

96%

114 rated

Answer

Error 1: The student drew the start line in ink instead of using a pencil.

Problem 1: If the start line is drawn in ink, it may dissolve in the solvent, leading to unclear results as the ink will mix with the solvent, causing inaccurate measurements.

Error 2: The solvent was placed above the start line.

Problem 2: If the solvent is above the start line, it can dissolve the colours before the experiment begins, resulting in potential mixing and incorrect distances travelled by the colours.

Step 2

Give two conclusions the student can make from Figure 2 about the four colours in the brown ink.

99%

104 rated

Answer

  1. The brown ink contains blue, yellow, and red colours, but no green colour.

  2. The blue colour is likely the most soluble since it travelled the furthest distance in comparison to the other colours.

Step 3

Why was the green colour still on the start line at the end of the experiment?

96%

101 rated

Answer

The green colour was insoluble in the solvent.

Step 4

Calculate the distance the solvent moved.

98%

120 rated

Answer

Using the Rf equation:

Rf=distance moved by colourdistance moved by solventRf = \frac{distance~moved~by~colour}{distance~moved~by~solvent}

Substituting the values:

0.24=1.8 cmdistance moved by solvent0.24 = \frac{1.8~cm}{distance~moved~by~solvent}

Rearranging gives:

distance moved by solvent = \frac{1.8cm}{0.24} = 7.5cm.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;