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This question is about electrolysis - AQA - GCSE Chemistry - Question 7 - 2019 - Paper 1

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This question is about electrolysis. Aluminium is produced by electrolysing a molten mixture of aluminium oxide and cryolite. 07.1 Explain why a mixture is used as... show full transcript

Worked Solution & Example Answer:This question is about electrolysis - AQA - GCSE Chemistry - Question 7 - 2019 - Paper 1

Step 1

Explain why a mixture is used as the electrolyte instead of using only aluminium oxide.

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Answer

A mixture is used because it has a lower melting point than pure aluminium oxide, which reduces energy requirements during electrolysis. Additionally, the presence of cryolite enhances the efficiency of the process.

Step 2

What happens at the negative electrode during the production of aluminium?

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Answer

Aluminium ions gain electrons.

Step 3

Complete the balanced half-equation for the process at the positive electrode.

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Answer

4OH⁻ → O2 + 2H2O + 4e⁻

Step 4

Explain why the positive electrode must be continually replaced.

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Answer

The positive electrode must be continually replaced because it reacts with oxygen to form carbon dioxide and is gradually consumed during the process.

Step 5

Calculate the mass of oxygen produced when 2000 kg of aluminium oxide is completely electrolysed.

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Answer

First, determine the number of moles of Al2O3: n=2000 kg102 g/mol=19608 moln = \frac{2000 \text{ kg}}{102 \text{ g/mol}} = 19608 \text{ mol} For every 2 moles of Al2O3, 3 moles of O2 are produced: O2=19608×32=29412 mol\text{O}_2 = 19608 \times \frac{3}{2} = 29412 \text{ mol} Next, calculate the mass of O2: mass=29412 mol×32 g/mol=941kg\text{mass} = 29412 \text{ mol} \times 32 \text{ g/mol} = 941 kg

Step 6

Explain why sodium chloride solution cannot be used as the electrolyte to produce sodium metal.

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Answer

Sodium chloride solution cannot be used because, during electrolysis, hydrogen gas would be produced instead of sodium due to sodium's higher reactivity compared to hydrogen.

Step 7

Calculate the volume of 150 kg of chlorine gas at room temperature and pressure.

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Answer

To find the volume, first convert the mass of Cl2 into moles: n=150000extg71extg/mol2113extmoln = \frac{150000 ext{ g}}{71 ext{ g/mol}} \approx 2113 ext{ mol} Using the ideal gas law, the volume at RTP is: V=n×24.0extdm3=2113×24.0=50700extdm3V = n \times 24.0 ext{ dm}^3 = 2113 \times 24.0 = 50700 ext{ dm}^3

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