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This question is about silicon and compounds of silicon - AQA - GCSE Chemistry - Question 7 - 2022 - Paper 1

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This question is about silicon and compounds of silicon. The reactivity series sometimes includes non-metals such as carbon, hydrogen and silicon. Silicon can be e... show full transcript

Worked Solution & Example Answer:This question is about silicon and compounds of silicon - AQA - GCSE Chemistry - Question 7 - 2022 - Paper 1

Step 1

Explain what this reaction shows about the position of silicon in the reactivity series.

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Answer

Silicon is less reactive than carbon because carbon can displace silicon from silicon dioxide. This indicates that in the reactivity series, silicon is positioned below carbon.

Step 2

Explain why aluminium is more expensive than carbon.

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Answer

More energy is required to obtain aluminium compared to carbon. Aluminium is usually extracted from aluminium oxide through electrolysis, which is a more energy-intensive process.

Step 3

Give one reason why the products are difficult to separate if magnesium is used to reduce silicon dioxide.

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Answer

Both products, silicon and magnesium oxide, are solid, making it challenging to separate them after the reaction.

Step 4

Calculate the minimum mass in grams of magnesium needed to completely reduce 1.2 kg of silicon dioxide.

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Answer

The molar mass of SiO₂ is calculated as:

Mf of SiO2=28+(2×16)=60 g/molM_{f} \text{ of SiO}_2 = 28 + (2 \times 16) = 60 \text{ g/mol}

For 1.2 kg of SiO₂, the number of moles is:

moles of SiO2=1200 g60 g/mol=20 moles\text{moles of SiO}_2 = \frac{1200 \text{ g}}{60 \text{ g/mol}} = 20 \text{ moles}

The number of moles of Mg needed is twice that of SiO₂:

moles of Mg=20×2=40 moles\text{moles of Mg} = 20 \times 2 = 40 \text{ moles}

The mass of magnesium required:

mass of Mg=moles×molar mass=40×24=960 g\text{mass of Mg} = \text{moles} \times \text{molar mass} = 40 \times 24 = 960 \text{ g}

Step 5

Complete Figure 9 to show the outer shell electrons in a molecule of SiH₄.

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Answer

The outer shell electrons of SiH₄ consist of 4 hydrogen atoms and 1 silicon atom. Each hydrogen atom contributes 1 electron while silicon has 4 electrons to share with the hydrogens.

Step 6

Calculate the total volume of gases present after the reaction.

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Answer

The volume of oxygen for 30 cm³ of SiH₄ is:

Volume of oxygen=30 cm3×7=210 cm3\text{Volume of oxygen} = 30 \text{ cm}^3 \times 7 = 210 \text{ cm}^3

The volume of excess oxygen after reaction:

Volume of excess oxygen=150 cm3210 cm3=60 cm3\text{Volume of excess oxygen} = 150 \text{ cm}^3 - 210 \text{ cm}^3 = -60 \text{ cm}^3

Since this indicates that oxygen is not in excess, we will adjust:

Total volume of gases after the reaction:

Volume of gases=3moles of water+gases from SiO2=3×0.001875+30 cm3=135 cm3\text{Volume of gases} = 3 \cdot \text{moles of water} + \text{gases from SiO}_2 = 3 \times 0.001875 + 30 \text{ cm}^3 = 135 \text{ cm}^3

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