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This question is about sulfuric acid (H₂SO₄) and ethene - AQA - GCSE Chemistry - Question 4 - 2017 - Paper 1

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This question is about sulfuric acid (H₂SO₄) and ethene. Sulfuric acid is used to produce copper sulfate (CuSO₄). The equation for the reaction is: CuO(s) + H₂SO₄... show full transcript

Worked Solution & Example Answer:This question is about sulfuric acid (H₂SO₄) and ethene - AQA - GCSE Chemistry - Question 4 - 2017 - Paper 1

Step 1

Describe a method for making copper sulfate crystals from copper oxide and sulfuric acid.

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Answer

To make copper sulfate crystals from copper oxide and sulfuric acid, follow these steps:

  1. Addition: Start by adding copper oxide to dilute sulfuric acid in a beaker. Ensure there is sufficient copper oxide to react with all of the acid.

  2. Reaction: The mixture should be stirred until the copper oxide has completely reacted.

  3. Filtration: Filter the mixture to remove any excess copper oxide that has not reacted, yielding a clear copper sulfate solution.

  4. Crystallization: Heat the filtered solution gently to evaporate some of the water, then allow it to cool gradually. Crystals of copper sulfate will form as the solution evaporates.

Step 2

Calculate the mass of copper oxide required to produce 24.95 g of copper sulfate crystals (CuSO₄·5H₂O).

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Answer

To calculate the mass of copper oxide needed, use the formula:

  1. Determine the molar masses:

    • Molar mass of CuSO₄·5H₂O = 249.5 g/mol.
    • Molar mass of CuO can be calculated as follows:
      • M(Cu) = 63.5 g/mol,
      • M(O) = 16 g/mol

    Therefore, M(CuO) = 63.5 + 16 = 79.5 g/mol.

  2. Moles of copper sulfate: Calculate moles of CuSO₄·5H₂O produced:

    n=massmolar mass=24.95249.50.1molesn = \frac{mass}{molar \ mass} = \frac{24.95}{249.5} \approx 0.1 \, \text{moles}

  3. Stoichiometry: From the balanced equation, 1 mole of CuSO₄ is produced from 1 mole of CuO. Thus, moles of CuO needed = 0.1.

  4. Mass of copper oxide: Finally, calculate the mass of CuO:

    mass=moles×molar mass=0.1moles×79.5g/mol=7.95gmass = moles \times molar \ mass = 0.1 \, \text{moles} \times 79.5 \, g/mol = 7.95 \, g

Step 3

How does the wealth of countries relate to their production of ethene and sulfuric acid?

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Answer

From the data in Table 1, it can be seen that as wealth decreases, ethene production tends to decrease as well, with the exception of country C or D.

Furthermore, the production of sulfuric acid does not appear to be linked to the wealth of a country, as it varies independently of the wealth values presented.

Step 4

Suggest why the use of ethene has increased in the last 50 years.

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Answer

The use of products of ethene has increased largely due to advancements in polymer technologies and the growing demand for plastics. Ethene is a key raw material in the production of various polymers used in everyday items, thereby significantly raising its demand over time.

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