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This question is about potassium and its compounds - AQA - GCSE Chemistry - Question 4 - 2017 - Paper 3

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This question is about potassium and its compounds. 4 (a) (i) Potassium reacts with water to produce potassium hydroxide solution and a gas. Figure 8 shows the app... show full transcript

Worked Solution & Example Answer:This question is about potassium and its compounds - AQA - GCSE Chemistry - Question 4 - 2017 - Paper 3

Step 1

Complete and balance the equation for the reaction.

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Answer

The balanced equation for the reaction is:

ightarrow 2 ext{KOH} + ext{H}_2$$ This shows that 2 moles of potassium react with 2 moles of water to produce 2 moles of potassium hydroxide and 1 mole of hydrogen gas.

Step 2

Give two differences you would see between the reactions of potassium and lithium with water.

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Answer

  1. Reaction Speed: Potassium reacts more vigorously than lithium, producing hydrogen gas rapidly.

  2. Flame Color: When potassium reacts with water, it produces a lilac flame, while lithium does not produce a flame.

Step 3

Describe how a student could do titrations to find the mean volume of potassium hydroxide solution which would neutralise 25.00 cm³ of nitric acid.

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Answer

  1. Preparation: Fill a burette with potassium hydroxide solution and place a conical flask under it containing the nitric acid solution.

  2. Indicator: Use an appropriate indicator to visualize the endpoint, such as phenolphthalein.

  3. Titration Process: Slowly add the potassium hydroxide from the burette to the nitric acid while stirring continuously until the indicator changes color.

  4. Reading the Burette: Record the volume of potassium hydroxide used at the point of color change.

  5. Repeat: Repeat the titration two or three times to ensure accuracy and calculate the mean volume from the data collected.

Step 4

Calculate the concentration of the nitric acid.

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Answer

To find the concentration of nitric acid, we first use the formula:

extC1imesextV1=extC2imesextV2 ext{C}_1 imes ext{V}_1 = ext{C}_2 imes ext{V}_2

Where:

  • C1C_1 = concentration of potassium hydroxide (0.20 mol/dm³)
  • V1V_1 = volume of potassium hydroxide used (26.25 cm³ = 0.02625 dm³)
  • C2C_2 = concentration of nitric acid (unknown)
  • V2V_2 = volume of nitric acid (25.00 cm³ = 0.02500 dm³)

Substituting the known values:

0.20imes0.02625=C2imes0.025000.20 imes 0.02625 = C_2 imes 0.02500

Solving for C2C_2 gives:

C2=0.20imes0.026250.02500=0.21extmol/dm3C_2 = \frac{0.20 imes 0.02625}{0.02500} = 0.21 ext{ mol/dm³}

Therefore, the concentration of the nitric acid is 0.21 mol/dm³.

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