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This question is about potassium and its compounds - AQA - GCSE Chemistry - Question 4 - 2017 - Paper 3

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This question is about potassium and its compounds. 4 (a) (i) Potassium reacts with water to produce potassium hydroxide solution and a gas. Figure 8 shows the app... show full transcript

Worked Solution & Example Answer:This question is about potassium and its compounds - AQA - GCSE Chemistry - Question 4 - 2017 - Paper 3

Step 1

Complete and balance the equation for the reaction.

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Answer

The balanced equation for the reaction of potassium with water is:

2K+2H2O2KOH+H22 \text{K} + 2 \text{H}_2\text{O} \rightarrow 2 \text{KOH} + \text{H}_2

This equation shows that two moles of potassium react with two moles of water to produce two moles of potassium hydroxide and one mole of hydrogen gas.

Step 2

Give two differences you would see between the reactions of potassium and lithium with water.

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Answer

  1. Potassium reacts more vigorously with water compared to lithium, leading to more vigorous bubbling and potentially an explosive reaction.

  2. Potassium produces a lilac flame when ignited, while lithium produces a crimson flame.

Step 3

Describe how a student could do titrations to find the mean volume of potassium hydroxide solution which would neutralise 25.00 cm³ of nitric acid.

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Answer

  1. Prepare the potassium hydroxide solution in a burette.

  2. Place 25.00 cm³ of nitric acid in a conical flask and add a few drops of suitable indicator.

  3. Slowly release the potassium hydroxide from the burette into the conical flask while swirling the flask.

  4. Continue adding until the indicator changes colour, indicating neutralization.

  5. Record the volume of potassium hydroxide used and repeat the process to find the mean volume.

Step 4

Calculate the concentration of the nitric acid.

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Answer

To find the concentration of nitric acid:

  1. Calculate the moles of potassium hydroxide used:

    Moles of KOH = Volume (in dm³) × Concentration = 0.02625 , dm³ × 0.20 , mol/dm³ = 0.00525 , moles

  2. From the balanced equation, the mole ratio of KOH to HNO₃ is 1:1, so moles of HNO₃ = 0.00525.

  3. Calculate the concentration of HNO₃:

    Concentration = Moles/Volume = 0.00525 , moles / 0.025 , dm³ = 0.21 , mol/dm³.

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